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3 years ago

4 (×+2) show step if you can

Mathematics

2 answers:

chubhunter [2.5K]3 years ago

5 0

I believe the answer is 4x + 8. you multiply 4 by x which makes 4x. Than you multiply 4 by 2, making 8.

Alona [7]3 years ago

3 0

This problem appears to be linked with the Distributive Property. The Distributive Property allows any outside number/variable of the parenthesis to multiply with all inside numbers/variables within the parenthesis.

For example:

2(1 + 3)
2(1) + 2(3)
2 + 6
8.

With our definition, rule, and example, we are ready to solve.

4(x + 2)
Multiply the outside number (4) by all inside numbers/variables (x + 2).
4(x) + 4(2)
4x + 8.
If this is not solving for x, this is your answer.

If we are solving for x, we need to get 4x by itself and then simplify if possible.

4x + 8 = 0
Remember, what you do to one side of the equation you must do to the other.
Subtract 8 from both sides.
4x = -8
Divide both sides by 4.

4x / 4 = x
-8 / 4 = -2
X = -2

Your answers are:

4x + 8 if simplifying the expression.
x = -2 if we are solving for x.

I hope this helps!

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Will give brainliest, please help fast

Gekata [30.6K]

Answer:

Converting the equation $x^2-20x+13=0$ into completing the square method we get: $\mathbf{(x-10)^2=87}$

Step-by-step explanation:

we are given quadratic equation: $x^2-20x+13=0$

And we need to convert it into completing the square method.

Completing the square method is of form: $a^2-2ab+b^2=(a-b)^2$

Looking at the given equation $x^2-20x+13=0$

We have a = x

then we have middle term 20x that can be written in form of 2ab So, we have a=x and b=? Multiplying 10 with 2 we get 20 so, we can say that b = 20

So, 20x in form of 2ab can be written as: 2(x)(10)

So, we need to add and subtract (10)^2 on both sides

$x^2-20x+13=0\\x^2-2(x)(10)+(10)^2-(10)^2+13=0\\(x^2-2(x)(10)+(10)^2) \:can\: be\: written\: as\: (x-10)^2 \\(x-10)^2-100+13=0\\(x-10)^2-87=0\\(x-10)^2=87$

So, converting the equation $x^2-20x+13=0$ into completing the square method we get: $\mathbf{(x-10)^2=87}$

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3 years ago

Whats the sum of 2x and 3

rjkz [21]

Answer:

5x maybe dont take my word

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3 years ago

Point C divides segment AB so that AC:AB is 2:9. Which statement is NOT true?

jeka94

Answer:

A. Point C divides segment AB so that AC:CB is 1:3

or either c

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4 years ago

There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con

grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

$\square ABCD$

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$

$\angle BAC = \angle DCA$

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

$\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$

and

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$

So, the congruent sides and angles of △ABE and △CDE are:

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$ ---- S

$\angle BAC = \angle DCA$ ---- A

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$ or $\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$ --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

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3 years ago

To solve a system of inequalities so you can graph it how do you change these two equations into something like the two that are

Zigmanuir [339]

Explanation

Problem #2

We must find the solution to the following system of inequalities:

$\begin{gathered} 3x-2y\leq4, \\ x+3y\leq6. \end{gathered}$

(1) We solve for y the first inequality:

$-2y\leq4-3x.$

Now, we multiply both sides of the inequality by (-1), this changes the signs on both sides and inverts the inequality symbol:

$\begin{gathered} 2y\ge-4+3x, \\ y\ge\frac{3}{2}x-2. \end{gathered}$

The solution to this inequality is the set of all the points (x, y) over the line:

$y=\frac{3}{2}x-2.$

This line has:

• slope m = 3/2,

• y-intercept b = -2.

(2) We solve for y the second inequality:

$\begin{gathered} x+3y\leq6, \\ 3y\leq6-x, \\ y\leq-\frac{1}{3}x+2. \end{gathered}$

The solution to this inequality is the set of all the points (x, y) below the line:

$y=-\frac{1}{3}x+2.$

This line has:

• slope m = -1/3,

• y-intercept b = 2.

(3) Plotting the lines of points (1) and (2), and painting the region:

• over the line from point (1),

• and below the line from point (2),

we get the following graph:

Answer

The points that satisfy both inequalities are given by the intersection of the blue and red regions:

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1 year ago