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kvasek [131]
2 years ago
15

A bag contains 3 triangles, 4 squares, 5 pentagons, and 6 hexagons. If one shape is randomly chosen, what is the probability tha

t a hexagon is chosen?​
Mathematics
1 answer:
e-lub [12.9K]2 years ago
3 0

I’d say that it’s definitely random choice for the squares, pentagons, and hexagons. But, if we are looking at how common it would be between the 3 of them, then I would say that it would be one of the hexagons, because there are more hexagons than any of the other shapes in the bag.

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riadik2000 [5.3K]

Answer:

10 ft

Step-by-step explanation:

Use theorem pythagoras

Length = x

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the answer is 10 because length can't be in negative number

4 0
2 years ago
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Shkiper50 [21]

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Step-by-step explanation:

4 0
2 years ago
I don’t understand this
egoroff_w [7]

Answer: OPTION A

Step-by-step explanation:

The distance between any number is always positive so we should apply the absolute value.

The distance between numbers=number 1-number2 (or vise versa, and that is why we need absolute value)

In your question, the two numbers are 3/4 and 2. Applying to the expression above, the distance between two numbers should be |3/4-2| or |2-3/4|.

The only option in your case is |3/4-2| and this is it.

Hope this helps!! :)

Please let me know if you have any question

5 0
3 years ago
Solve for x: 5x + 2 = 4x - 9.
AlekseyPX

Answer:

Step-by-step explanation:

5x + 2 = 4x - 9

Collecting like terms

5x - 4x = -9 - 2

x = -11

4 0
2 years ago
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alexandr1967 [171]

Answer:

4(19x + 17)

Step-by-step explanation:

76x + 68 both numbers are divided by 4 so we fact out 4 and introduce the brackets : 4(19x + 17 )

7 0
2 years ago
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