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suter [353]
3 years ago
15

Find all solutions to the equation in the interval [0, 2pi). COS X = sin 2x​

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
6 0

Answer:

Step-by-step explanation:

cos x=sin 2x

sin 2x-cos x=0

2 sin x cos x-cos x=0

cos x(2 sin x-1)=0

either cos x=0

x=\frac{\pi }{2},\frac{3\pi }{2}

or

2 sin x-1=0

sin x=\frac{1}{2} =sin (\frac{\pi }{6}),sin(\pi -\frac{\pi }{6} )\\x=\frac{\pi }{6} ,\frac{5 \pi }{6}

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