What are the solution(s) to the quadratic equation 50

A 128-ounce jug of milk costs $3.20, and a 64-ounce jug of milk costs $2.24. What is the difference in cost per ounce between th

klasskru [66]

Answer:

The 64 ounce jug of milk costs $0.010 more per ounce than the 128 ounce jug of milk/

Step-by-step explanation:

3.20/128=$0.025 per ounce jug of milk

2.24/64=$0.035 per ounce jug of milk

0.035 - 0.025 = .010

5 0

3 years ago

Yall someone help I still have a bunch if other test and I'm so tired ;-;

g100num [7]

Me das mas información?

6 0

3 years ago

Sally went 3.5 miles per hour on a treadmill for 5 hours. She was sore and decided to take 400 mg of Advil. The half portion sta

xenn [34]

Answer:

8 hours

Step-by-step explanation:

it says: The half portion stays in her body for 8 hours.

8 0

4 years ago

Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i

kolezko [41]

Answer:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

Step-by-step explanation:

Data given and notation

Data: 801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=811$ represent the sample mean

$s=19.647$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =750$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

What do you conclude?

Compute the p-value

Since is a two tailed test the p value would be:

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B6%7D%7B3%20%2B%2011i%7D%20" id="TexFormula1" title=" \frac{6}{3 + 11i} " alt=" \f

Lorico [155]

(3+11i)/(3+11i)=1

So that means you can multiply 6/(3+11i) by (3+11i)/(3+11i)

Then 6(3+11i)/1

= 18+66i

7 0

3 years ago

What are the solution(s) to the quadratic equation 50 - x² = 0?