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Hatshy [7]
3 years ago
5

Please Answer! If the Alexanders completed the 735 mi. trip in 15 hr., what was their average rate of travel? Please explain you

r answer!
Mathematics
1 answer:
rusak2 [61]3 years ago
5 0

49 miles per hour

Since you want to find the average rate of travel, you have to divide 735 by 15.

This way you would be able to the the average rate of change.

When you find averages you would add all the numbers and divide it by how many numbers there are.

If you add 49, 15 times and divide it by 15 you would be about to get 49.

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Round to the nearst tenth
Serga [27]

Answer:

Step-by-step explanation:

4 0
3 years ago
Use graph to answer question
slamgirl [31]

Answer:

cos(θ) = 3/5

Step-by-step explanation:

We can think of this situation as a triangle rectangle (you can see it in the image below).

Here, we have a triangle rectangle with an angle θ, such that the adjacent cathetus to θ is 3 units long, and the cathetus opposite to θ is 4 units long.

Here we want to find cos(θ).

You should remember:

cos(θ) = (adjacent cathetus)/(hypotenuse)

We already know that the adjacent cathetus is equal to 3.

And for the hypotenuse, we can use the Pythagorean's theorem, which says that the sum of the squares of the cathetus is equal to the square of the hypotenuse, this is:

3^2 + 4^2 = H^2

We can solve this for H, to get:

H = √( 3^2 + 4^2) = √(9 + 16) = √25 = 5

The hypotenuse is 5 units long.

Then we have:

cos(θ) = (adjacent cathetus)/(hypotenuse)

cos(θ) = 3/5

5 0
3 years ago
Express the product of 2xsquared+6x-8 and x+3 in standard form
postnew [5]

Answer:

2x^3+12x^2+10x-24

Step-by-step explanation:

(2x^2+6x-8)(x+3)

2x^3+6x^2-8x+6x^2+18x-24

2x^3+6x^2+6x^2-8x+18x-24

2x^3+12x^2+10x-24

4 0
4 years ago
Solve the proportion for the variable given <br> 4/6=9/x<br> a.10<br> b.6<br> c.1<br> d. 27/2
e-lub [12.9K]

Step-by-step explanation:

Option D is the correct answer because we will cross multiply

4/6 = 9/x

4x = 54

X = 27/2

5 0
3 years ago
What is the solution to: <br> T/t-4=t+4/6
S_A_V [24]
\frac{t}{t-4}= \frac{t+4}{6} \\ t \neq 4 \\ 6t=  (t+4)(t-4) \\ 6t=t^2-16 \\ t^2-6t-16=0 \\ D=b^2-4ac=(-6)^2-4*1*(-16)=36+64=100 \\ t_{1,2}= \frac{-bб \sqrt{D} }{2a}  \\ t_1= \frac{6-10}{2}=-2 \\  \ t_2= \frac{6+10}{2}=8

Answer: t=-2, t=8
4 0
3 years ago
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