m∠FDE = 52°
Solution:
Given data:
DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠ABF + m∠CBF = 180°
116° + m∠CBF = 180°
m∠CBF = 64°
If CD || BE, then CD || BF.
Hence CD || BE and BE || FD.
Therefore BFCD is a parallelogam.
<em>In parallelogram, Adjacent angles form a linear pair.</em>
m∠CBF + m∠BFD = 180°
64° + m∠BFD = 180°
m∠BFD = 116°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠BFD + m∠DFE = 180°
116° + m∠DFE = 180°
m∠DFE = 64°
we know that DE ≅ DF.
<em>In triangle, angles opposite to equal sides are equal.</em>
m∠DFE = m∠DEF
m∠DEF = 64°
<em>sum of all the angles of a triangle = 180°</em>
m∠DFE + m∠DEF + m∠FDE = 180°
64° + 64° + m∠FDE = 180°
m∠FDE = 52°
Answer:
Final Value = 58.50 × (1 + 10/100)
Final Value = 58.50 × (1 + 0.1)
Final Value = 58.50 × (1.1)
Final Value = 64.35
A) Is {a, e,i,o,u} a subset of {a,b,c,d,e,f,g,h,i) <br> Why?<br>
kozerog [31]
Answer:
No
Step-by-step explanation:
u and o arent elements of {a, b, c, d, e, f, g, h, i}
The parabola divises the plan into 2 parts. Part 1 composes the point A, part 2 composes the points C, D, F.
+ All the points (x;y) satisfies: -y^2+x=-4 is on the <span>parabola.
</span>+ All the points (x;y) satisfies: -y^2+x< -4 is in part 1.
+ All the points (x;y) satisfies: -y^2+x> -4 is in part 2<span>.
And for the question: "</span><span>Which of the points satisfy the inequality, -y^2+x<-4"
</span>we have the answer: A and E
6 ft into meters would be 1.829, rounding to to nearest tenth would be 1.8
