<span>Cancel <span>r2</span>
</span><span><span><span>(s4t)</span>/(</span><span>s<span>t3)</span></span></span>
2 <span>Use Quotient Rule: <span><span><span>xa/</span><span>xb</span></span>=<span>x^<span>a−b</span></span></span>
</span><span><span>s^<span>4−1</span></span><span>t^<span>1−3</span></span></span>
3 <span>Simplify <span>4−1</span> to 3
</span><span><span>s^3</span><span>t^<span>1−3</span></span></span>
4 <span>Simplify <span>1−3</span> to <span>−2</span>
</span><span><span>s^3</span><span>t^<span>−2</span></span></span>
5 <span>Use Negative Power Rule:<span><span>x^<span>−a</span></span>=<span>1/<span>xa</span></span></span>
</span><span><span>s^3</span>×<span>1/<span>t2</span></span></span>
6 <span>Simplify
</span><span><span>(s3)/(</span><span>t2)</span></span>
Done so the answer is a. then
To solve this
problem, let us analyze this step by step. The temperature for each day is as
follows:
Water temperature
on Sunday = 78 degrees F
Water temperature
on Monday = changed by -3 degrees F
Water temperature
on Tuesday = changed by 3 degrees F
We can see that
the total change of water temperature from Sunday to Tuesday is:
-3 + 3 = 0
Therefore there
is zero overall change. There the integer which represents the temperature
change is “0”.
Since the overall
change in water temperature is zero, hence the temperature on Sunday and on
Tuesday is similar.
Water temperature
on Tuesday = 78 degrees F
Answer:
no they don't one lies in quadrant 1 while the other is in quadrant 3
Step-by-step explanation:
