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Afina-wow [57]
3 years ago
6

Solve 5=11-1/3 please i need this

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
8 0

Answer: look at the point

Step-by-step explanation:

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Step-by-step explanation:

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a random sample of 510 high school students has a normal distribution. The sample mean average ACT exam score was 21 with a 3.2
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Answer:

CI = 21 ± 0.365

Step-by-step explanation:

The confidence interval is:

CI = x ± SE * CV

where x is the sample mean, SE is the standard error, and CV is the critical value (either t score or z score).

Here, x = 21.

The standard error for a sample mean is:

SE = σ / √n

SE = 3.2 / √510

SE = 0.142

The critical value is looked up in a table or found with a calculator.  But first, we must find the alpha level and the critical probability.

α = 1 - 0.99 = 0.01

p* = 1 - (α/2) = 1 - (0.01/2) = 0.995

Using a calculator or a z-score table:

P(x<z) = 0.995

z = 2.576

Therefore:

CI = 21 ± 0.142 × 2.576

CI = 21 ± 0.365

Round as needed.

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4 years ago
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Step-by-step explanation:

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