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Kobotan [32]
3 years ago
5

Peter has changed his diet to eat healthier. 2/3 of his meals are gluten free and of those gluten free meals 1/2 are vegan. How

much of his total diet is gluten free and vegan?
Mathematics
1 answer:
vfiekz [6]3 years ago
4 0
1 1/2 of his total diet in gluten free and vegan
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If a and b are odd integers, then a – b is an even integer.
Readme [11.4K]
So the answer choices are
1. a-b=even
2. a and b are not odd
3. a and b are odd
4. a-b=even
5. a-b=not even

even=not odd
not even=odd so choice 5 is really a-b=odd
basically choice 4 and 1 are the same so we cross one out
so
the problem said that a and b are odd so therefor choice2 is wrong and choice 3 is correct

then both are odd
odd-odd=even because
an even number is represented as 2n where n is an integer
an odd number can be represented as 2n+1 so assume you have 2 odd numbers 2 away from each other so odd and (odd+2)
odd+2-odd=2n+1+2-(2n+1)=2n+1+2-2n-1=2n-2n+1-1+2=2
you are left with odd
using integers
7 and 11
11-7=4
even

so odd-odd=even, it depends on weather you consider 0 odd or even


so the asnwers are:
a and b are odd
a-b is not an even integer
6 0
3 years ago
Read 2 more answers
The product of 8 and the difference of 3 and a number
Neko [114]

Answer:

<h3>3 More than the Product of 8 and a Number is 8n + 3.</h3>

Step-by-step explanation:

<h3>mark as brainliast</h3><h3>indian genius sarthak</h3>
3 0
3 years ago
What is the product? (-2x -9y2) (-4x-3)
lutik1710 [3]

Answer:

8x^4+36x^3y^2

Step-by-step explanation:

(-2x-9y^2)(-4x^3)

8x^4+36x^3y^2

6 0
3 years ago
A report states that the mean yearly salary offer for students graduating with a degree in accounting is $48,734. Suppose that a
DENIUS [597]

Solution :

To claim to be tested is whether "the mean salary is higher than 48,734".

i.e. μ > 48,734

Therefore the null and the alternative hypothesis are

$H_0 : \mu = 48,734$

and $H_1 : \mu > 48,734$

Here, n = 50

$\bar x = 49,830$

s = 3600

We take , α = 0.05

The test statistics t is given by

$t=\frac{\bar x - \mu}{\frac{s}{\sqrt n}}$

$t=\frac{49,830 - 48,734}{\frac{3600}{\sqrt 50}}$

t = 2.15

Now the ">" sign in the $H_1$ sign indicates that the right tailed test

Now degree of freedom, df = n - 1

                                              = 50 - 1

                                              = 49

Therefore, the p value = 0.02

The observed p value is less than α = 0.05, therefore we reject $H_0$. Hence the mean salary that the accounting graduates are offered from the university is more than the average salary of 48,734 dollar.

3 0
3 years ago
The scale factor of a model of a swimming pool to the actual swimming pool is 1 to 20. the volume of the actual pool is 400 m^3.
erica [24]
P(v)=5000/v hope this helps
3 0
3 years ago
Read 2 more answers
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