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Rama09 [41]
3 years ago
15

How to divide 1/8 ÷ 4

Mathematics
2 answers:
Zinaida [17]3 years ago
8 0
Multiply 4 by its reciprocal: 1/8x1/4= 1/32.
Vika [28.1K]3 years ago
3 0
1/32 or 0.03125 would be you answer
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Which quadratic function is represented by the graph? 3 O y = 0.5(x + 2)2 + 4 O y = 0.5(x + 3)2 -0.5 O y = 0.5(x - 3)2 -0.5 O y
nadya68 [22]

Answer:

No solution is possible from the given information.

Step-by-step explanation:

This isn't Hogwarts.

If you don't include the graph we can't magically see it.

8 0
3 years ago
HELP giving brainlest and more points
cupoosta [38]

Answer:

4,000,000,000 meters

Step-by-step explanation:

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4 0
3 years ago
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The results of an analysis, on the makeup of garbage, done by the Environmental Protection Agency was published in 1990. Some of
shusha [124]

The results of an analysis, on the makeup of garbage, done by the Environmental Protection Agency was published in 1990. Some of the results are given in the following table, which for various years gives the number of pounds per person per day of various types of waste materials.

6 0
3 years ago
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Which is M=9pm solved for p
zaharov [31]
<h2>Answer:</h2>

<u>The value of </u><u>p :M/9m</u>

<h2>Explanation:</h2>

As we have been given value of M

Value of M=9pm

So we can find value of p from here by simple mathematics rule

M=9pm

divide both side with 9m so

M/9m=9pm/9m

we get value of p so M/9m=p.

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6 0
3 years ago
The amount of polonium-210 remaining, p(t), after t days in a sample can be modeled by the exponential function p(t) = 100e−0.00
Archy [21]

Answer:

% Po lost = 100[1 - e^(-0.005t)]  %; 73.0 g

Step-by-step explanation:

p(t) = 100e^(-0.005t)

Initial amount:        p(0) = 100

Amount remaining: p(t) = 100e^(-0.005t)

Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]

% of Po lost  = amount lost/initial amount × 100 %

= [1 - e^(-0.005t)]  × 100 % = 100[1 - e^(-0.005t)]  %

p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g

The mass of polonium remaining after 63 days is 73 g.

4 0
3 years ago
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