Answer:
the height (in feet) of the cliff is 121 ft
Explanation:
A stone hit the cliff with
speed, v = 88 ft/s
Acceleration, a= 32 ft/s^2
initial speed, u = 0 ft/s
height is h.
To solve this problem we will apply the linear motion kinematic equations, Equation of motion describes change in velocity, depending on the acceleration and the distance traveled
so, writing the formula of Equation of motion:
v^2 - u^2 = 2*a*h
substituting the appropriate values,
(88)^2 - 0 = 2*32* h
h=(88)^2 / 64
h= 121 ft
hence
the height (in feet) of the cliff is 121 ft
learn more about height of the cliff here:
<u>brainly.com/question/24130198</u>
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A :-) a = v^2 by r
Given - radius = 25 m
velocity = 10 m/s
Solution -
a = v^2 by r
a = ( 10 )^2 by 25
a = 100 by 25
( cut 25 and 100 because 25 x 4 = 100 )
a = 4 m/s^2
.:. The centripetal acceleration of the car
= 4 m/s^2.
Answer:
D. echolocation
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It's B. It divides only once is mitosis and twice in meiosis.