Answer:
The equation of the line y= 5x+1. Line that is parallel to the function given should have the same slope as the equation which is 5. We use the point-slope form in order to find the second equation that contains the point (4,5).
y - 5 = 5(x-4)
y = 5x - 20 +5
y≈ 5x -15
Answer:
27 grams of sugar
Step-by-step explanation:
If 1/3 candy contains 12 grams of sugar
Then 3/4 candy contains C grams of sugar
C= 3/4 * 12grams➗1/3=3*12*3grams➗4=108grams➗4=27 grams of sugar
Answer:
=135.53°
Step-by-step explanation:
The bearing that the captain should turn is the angle difference between the two islands from the position of the ship.
Let C be the position of the ship, then
AB is c=160
AC is b=220
BC is a=200
We use the cosine rule as follows:
c²=a²+b²-2ab Cos C
160²=200²+220²-2×200×220 Cos C
25600=88400-88000Cos C
88000 Cos C=88400-25600
88000Cos C=62800
Divide both sides by 88000.
Cos C=62800/88000
=0.7136
C=44.47°
He should turn (180°-44.47°)=135.53°
Answer:
I would go with c
Step-by-step explanation:
if it is incorrect sorry
Answer:
a) 820
b)450
c) -540
d) -294
e) 1440
f) 1425
Step-by-step explanation:
a) it is an arithmetic progression with ratio=4
a1=3,
a2=3+r=3+4=7.....
a20=a1+19r
so a20=3+19*4=3+76=79
S=(a1+an)*n/2 where n=20
so S=(3+79)*20/2=820
b) a15=a1+14*r=2+14*4=2+56=58
S=(a1+a15)*15/2=(2+58)*15/2=60*15/2=30*15=450
It is the same formula for all the exercises
S=(a1+an)*n/2 , where n is the number of terms
c) a40=30+39*(-3)=30-87=-57
So S=(30-57)*40/2=-540
d) a14=5+13*(-4)=5-52=-47
S=(5-47)*14/2=-42*14/2=-42*7=-294
e) it is 5+7+9+......+75
nr of terms = (an-a1) :r+1=(75-5):2+1=36
S=(5+75)*36/2=36*40=1440
f) ratio=7-4=3
the same formula for n= (91-4):3+1=87:3+1=29+1=30
S=(4+91)*30/2=95*30/2=2850/2=1425
