Math question Plz Help

Mathematics

1 answer:

astraxan [27]3 years ago

4 0

Answer:

-1/3x + 5

Step-by-step explanation:

The slope-intercept is y = mx + b

The m is the slope and b is the y-intercept.

The equation is:

y = -1/3x + 5

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Can you please help with both? :)

QveST [7]

Answer: 1. 12 2. 120

Step-by-step explanation:

1. so basically 9/6=18/x

since they are similir the'd have the same ratio

sooo you just solve for x (multiply 6 by 18, and then divide by 9) and you get 12

2. same thing except you put 6/10=12/x, and solve it (multiply 10 by 12 and divide by 6) and u get 20

dats how i would do it but there are other ways too im sure :)

hope this helps

8 0

3 years ago

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shap

11Alexandr11 [23.1K]

Answer:

0.25 feet per minute

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

$\dfrac{dV}{dt}=20$ ft^3/min$

$\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h$

Since base diameter = Height of the Cone

Radius of the Cone = h/2

Therefore,

$\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}$

$\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}$

Therefore: $\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=20$

We want to determine how fast is the height of the pile is increasing when the pile is 10 feet high.

$h=10$ feet$\\\\\dfrac{3\pi *10^2}{12}\dfrac{dh}{dt}=20\\25\pi \dfrac{dh}{dt}=20\\ \dfrac{dh}{dt}= \dfrac{20}{25\pi}\\ \dfrac{dh}{dt}=0.25$ feet per minute (to two decimal places.)$