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lozanna [386]
3 years ago
6

What is random access memory?

Computers and Technology
2 answers:
kogti [31]3 years ago
3 0
Memory that is in a computer

Hope this helped!!!
stiks02 [169]3 years ago
3 0
It is a type of computer memory that can be accessed randomly ;that is any type of memory can be accessed without touching the preceding bytes...it is the most common type of memory found in computers,and others devices ...Such as printers alsooo.....
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If Number = 7, what will be displayed after code corresponding to the following pseudocode is run? (In the answer options, new l
kherson [118]

Answer:

5,10; 6,12; 7,14

Explanation:

We will demonstrate the iteration of the loop:

First iteration: Number = 7, Count = 5 at the beginning. We will check if Count <= Number? Since it is correct, prints 5,10. Increment the Count by 1.

Second iteration: Number = 7, Count = 6. We will check if Count <= Number? Since it is correct, prints 6,12. Increment the Count by 1.

Third iteration: Number = 7, Count = 7. We will check if Count <= Number? Since it is correct, prints 7,14. Increment the Count by 1.

Forth iteration: Number = 7, Count = 8. We will check if Count <= Number? Since it is not correct, the loop stops.

8 0
3 years ago
If you want to distribute a formatted Microsoft word document to people who don't have word save it as a __file
Helga [31]
If you want them only to read it and not change it send as a .pdf else I would send as a .txt file. Hope that helps
5 0
2 years ago
Using Amdahl’s Law, calculate the speedup gain of an application that has a 60 percent parallel component for (a) two processing
Nina [5.8K]

Answer:

a) Speedup gain is 1.428 times.

b) Speedup gain is 1.81 times.

Explanation:

in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

t=\frac{1 }{(S + (1- S)/N) }

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.

(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t = \frac{1}{(0.4 + (1-0.4)/2)} =1428671

Speedup gain is 1.428 times.

(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t=\frac{1}{(0.4 + (1-0.4)/4)} = 1.8181

Speedup gain is 1.81 times.

8 0
3 years ago
Given the number of rows and the number of columns, write nested loops to print a rectangle. (PYTHON)
Allushta [10]

Answer:

Explanation:

Please see the attached picture for help.

6 0
3 years ago
Read 2 more answers
This is a device that enables computers to be connected to a network.
zhuklara [117]

The answer to your question is,

NIC - Network Interface Card

-Mabel <3

8 0
3 years ago
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