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3 years ago

8

3/4x + 11 < .3x + 3/4Solve inequality. pls

1 answer:

Rashid [163]3 years ago

7 0

<span><span><span><span>3/4</span>x</span>+11 </span>< <span><span>0.3x</span>+<span>3/4
</span></span></span>First turn 3/4 from both sides to decimals to get..
.75x+11 < 0.3x+.75
And then subtract 0.3x from both sides to get
.45x+11 < .75
And then subtract 11 from both sides to get
.45x < -10.25
And then divide both sides by .45x to get
x < -22.77777778

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What is the solution to y-7>3+2y

Alex17521 [72]

Solving:

-7 + y = 3 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.

-7 + y + -2y = 3 + 2y + -2y

Combine like terms: y + -2y = -1y

-7 + -1y = 3 + 2y + -2y

Combine like terms: 2y + -2y = 0

-7 + -1y = 3 + 0

-7 + -1y = 3

Add '7' to each side of the equation.

-7 + 7 + -1y = 3 + 7

Combine like terms: -7 + 7 = 0

0 + -1y = 3 + 7

-1y = 3 + 7

Combine like terms: 3 + 7 = 10

-1y = 10

Divide each side by '-1'.

y = -10

Hope it helps. (:

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3 years ago

In triangle PQR, m∠P = 30°, m∠Q = 90°, and m∠R = 60°. If the triangle is rotated 90° clockwise about a point, what is the measur

bixtya [17]

m<P=60°

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2 years ago

Jin's mother estimates there is a half-gallon of fruit punch remaining in the container. There are actually 72 ounces of fruit p

Ivanshal [37]

Answer:

89%

Step-by-step explanation:

the real answer is 64 fluid ounces

64/72*100 which is 88.89% or 89%

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2 years ago

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2 years ago

Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

so

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

$x=\frac{-20(+)32} {8}=1.5\ in$ -----> the solution

$x=\frac{-20(-)32} {8}=-6.5\ in$

Part c) How wide are the photo and frame together?

$(4+2x)=4+2(1.5)=7\ in$

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2 years ago