Answer:
1) According to your choices, 3.
2) The other two points must be critical points/undefined (imaginary according to your choices)
3) Synthetic division
4) I don't see why the quadratic formula is a choice, but it's the last remaining option.
Answer:
the solution of the system is:
x = 1 and y = 2.
Step-by-step explanation:
I suppose that we want to solve the equation:
-6*x + 6*y = 6
6*x + 3*y = 12
To solve this, we first need to isolate one of the variables in one of the equations.
Let's isolate y in the first equation:
6*y = 6 + 6*x
y = (6 + 6*x)/6
y = 6/6 + (6*x)/6
y = 1 + x
Now we can replace this in the other equation:
6*x + 3*(1 + x) = 12
6*x + 3 + 3*x = 12
9*x + 3 = 12
9*x = 12 - 3 = 9
x = 9/9 = 1
Now that we know that x = 1, we can replace this in the equation "y = 1 + x" to find the value of y.
y = 1 + (1) = 2
Then the solution of the system is:
x = 1 and y = 2.
Answer:
A
Step-by-step explanation:
Noting that i² = - 1
Given
(7 - 3i)(8 + 4i) ← expand factors using FOIL
= 56 + 28i - 24i - 12i²
= 56 + 4i - 12(- 1)
= 56 + 4i + 12
= 68 + 4i → A
Answer:
a) 
b) 
Step-by-step explanation:
Use logarithm properties:
Then
a) 
b) 
Let us first find how much he is spending every year, to do this let's find his monthly expense and multiply it by 12.
Every month Cameron spends 1040 + 980 + 120 = 2140
To find out how much he spends yearly, multiply the monthly value by 12,
2140 x 12 = 25680
This value is more than his net income so he clearly has a surplus, but to check we can subtract 129 from every month to get:
(1040 + 980 + 120 - 129) = 2011
2011 x 12 = 24132, which shows that his budget is saving 129 surplus every month. Choice B is correct.
