Answer: For three traits inherited in a dominant/recessive pattern, the probability of an offspring in a trihybrid cross between parents heterozygous for all three traits to be recessive at exactly two of the three loci is 23/64.
Explanation: Let A, B and C represent the dominant alleles and a, b and c represent the recessive alleles. The genotype of each of the parent will be AaBbCc since it has been said to be heterozygous for all the three traits. There are eight (8) possible different types of gametes from each of the genotype. This can be calculated using 2^n where n is the number of heterozygous loci.
The number of heterozygous loci in the genotype AaBbCc is three (3). 2^3 = 8. The gametes are;
ABC
ABc
AbC
Abc
aBC
aBc
abC and
abc.
Therefore, sixty-four possible offsprings are expected from the cross AaBbCc x AaBbCc.
Out of these offsprings, twenty-three (23) are expected to be heterozygous at two loci as boldly shown in the attached image.
Out of the choices given, the example of an eukaryote is yeast. The correct answer will be C.
Answer: B)
The chemical composition of the cell walls of each in the two kingdoms varies.
Explanation: Usatestprep
Answer:
If an organism has a beneficial trait, they have a higher chance of survival, and if they can survive they can reproduce too.
Example: Speckled moths camouflage with the bark of trees and are not easily seen by predators. Black moths do not camouflage with the bark of trees and are easily seen by predators, therefore the black moths are eaten. Because the black moths have been eaten they cannot reproduce and pass on the trait for black wings to their offspring, but the speckled moths are able to reproduce because they survived and are able to pass on the speckled wing trait to their offspring.