Answer:
- A'(4, -4)
- B'(0, -3)
- C'(2, -1)
- D'(3, -2)
Step-by-step explanation:
The coordinate transformation for a 270° clockwise rotation is the same as for a 90° counterclockwise rotation:
(x, y) ⇒ (-y, x)
The rotated points are ...
A(-4, -4) ⇒ A'(4, -4)
B(-3, 0) ⇒ B'(0, -3)
C(-1, -2) ⇒ C'(2, -1)
D(-2, -3) ⇒ D'(3, -2)
_____
<em>Additional comment</em>
To derive and/or remember these transformations, it might be useful to consider where a point came from when it ends up on the x- or y-axis.
A point must have come from the -y axis if rotating it 270° CW makes it end up on the +x-axis. A point must have come from the x-axis if rotating it 270° makes it end up on the +y axis. That is why we write ...
(x, y) ⇒ (-y, x) . . . . . . the new x came from -y; the new y came from x
Answer:
Maybe 15cm?
Step-by-step explanation:
14n-22 is the answer. Use the distributive property.
Step-by-step explanation:
-x+5+6x-7x-14
6x-8x+5-14
-2x-9
Answer:
George's mistake would be:
Instead of 2x + 40, she has made - x + 20.
Step-by-step explanation:
Slope - Intercept Form = y = mx + b
y + 20 = 2(x +20)
y + 20 = 2x + 40
- 20 - 20
----------------------
y = 2x + 20
(Should have been the answer)
BUT,
George's Solving:
y + 20 = 2(x + 20)
y + 20 = -x + 20
George's Mistake would be her miscalculation during her 2nd step. Where instead of distributing 2 to (x + 20), she has changed it to -x + 20, when in reality, it should have been 2x + 40.
