Answer:
a. Heterozygous individuals may pass on their copy of the disease-causing allele to offspring.
Explanation:
Tay-Sachs, which is a recessive lethal disease ---- Let say the recessive lethal diseases is s
∴ it only results when an individual posses two copies of the diseases-causing allele i.e two copies of the disease will be ss.
Now, when two hetrozygous individuals crossed , it is obvious that each can pass on their copy of the disease-causing allele to the offspring.
Let show an illustration for the above statement.
Let the heterozygous individual be Ts, if Ts cross with another Ts;
we will have:
Ts × Ts
T s
T TT Ts
s Ts ss
the offspring are TT,Ts,Ts,ss
We can now see how the Heterozygous individuals pass on their copy of the disease-causing allele to the offspring (Ts).
Synthesized RNA will remain. I believe this is because the polymerase allows the DNA to close up & that’s how it forms its double helix. Then the RNA chain is displaced and the DNA will soon be re-formed.
The answer is A.
You can remember this by thinking that since there was no change in the amino acid sequence, the mutation is silent in the fact that it didn't cause any trouble in the amino acid sequence.