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Mashcka [7]
3 years ago
6

Which planet's orbit around the sun is most nearly circular?

Chemistry
2 answers:
Lubov Fominskaja [6]3 years ago
8 0
The planet that orbits in a near circle is EARTH :D
Yuki888 [10]3 years ago
8 0
Venus is the planet with the smallest orbital eccentricity.  This sounds like more of a physics question, though.
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Define atomic numberand mass number. Which can vary without changing the identity of the element?
Volgvan

Explanation:

Atomic number is defined as the number of an element which represents total number of protons.

When an atom is neutral then it means it contains same number of protons and electrons.

On the other hand, atomic mass is defined as the sum of total number of protons and neutrons present in an atom.

Protons of every element remains fixed because it shows the identity of each element but if we change the number of neutrons then also identity of the atom will remain fixed. This is because changing the number of neutrons will not show any change in number of protons.

For example, ^{2}_{1}H and ^{3}_{1}H are isotopes of hydrogen and they have same number of protons but different number of neutrons.

Thus, we can conclude that number of neutrons can vary without changing the identity of the element.

8 0
3 years ago
A reaction between an acid and a base produced lithium chloride (LiCl). What acid and base combination could produce this salt?
dolphi86 [110]

C sulfuric acid and  magnesium hydroxide

5 0
3 years ago
Read 2 more answers
What is the excess reactant in the combustion of 23 g of methane in the open atmosphere?
Marta_Voda [28]

Answer : The excess reactant in the combustion of methane in opem atmosphere is O_{2} molecule.

Solution : Given,

Mass of methane = 23 g

Molar mass of methane = 16.04 g/mole

The Net balanced chemical reaction for combustion of methane is,

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

First we have to calculate the moles of methane.

\text{ Moles of methane}=\frac{\text{ Given mass of methane}}{\text{ Molar mass of methane}} = \frac{23g}{16.04g/mole} = 1.434 moles

From the above chemical reaction, we conclude that

1 mole of methane react with the 2 moles of oxygen

and 1.434 moles of methane react to give \frac{2moles\times 1.434moles}{1moles} moles of oxygen

The Moles of oxygen = 2.868 moles

Now we conclude that the moles of oxygen are more than the moles of methane.

Therefore, the excess reactant in the combustion of methane in open atmosphere is O_{2} molecule.


6 0
3 years ago
What is the density of a sample of the alloy pewter, (a mixture of tin and copper or lead) if a 7.11 cm3 sample has a mass of 53
xxTIMURxx [149]

Answer:

<h3>The answer is 7.47 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 53.137 g

volume = 7.11 cm³

We have

density =  \frac{53.137}{7.11}  \\  = 7.473558368...

We have the final answer as

<h3>7.47 g/cm³</h3>

Hope this helps you

5 0
3 years ago
HELP!!!<br> OPTIONS:<br> gas,<br> liquid,<br> solid
erica [24]

Answer:

Melting: solid liquid, Freezing: liquid to solid, Evaporation: liquid to gas.

Explanation:

mark me the brainliest

3 0
3 years ago
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