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3 years ago

Which planet's orbit around the sun is most nearly circular?

Chemistry

2 answers:

Lubov Fominskaja [6]3 years ago

8 0

The planet that orbits in a near circle is EARTH :D

Yuki888 [10]3 years ago

8 0

Venus is the planet with the smallest orbital eccentricity. This sounds like more of a physics question, though.

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Marco put a pot of water on to boil eggs. After a few minutes, all the water was gone. This is an example of ___.

kvv77 [185]

Answer:

evaporation

Explanation:

i think

4 0

3 years ago

On a mission to a newly discovered planet, an astronaut finds gallium abundances of 61.29% for 69Ga and 39.71% for 71Ga. What is

Verizon [17]

(exact weight of isotope #1) (abundance of isotope #1) + (exact weight of isotope #2) (abundance of isotope #2) = average atomic weight of the element(68.72*61.29) + (39.71*70.92) = 4211.84 + 2816.237028.07/100= 70.28

70.28 is the atomic mass of Gallium for the location

4 0

3 years ago

Where can most stars

Nesterboy [21]

Answer:

main sequence

Explanation:

The main sequence is a band of stars which includes most of them like our sun

5 0

3 years ago

Read 2 more answers

The stopcock connecting a 3.06 L bulb containing methane gas at a pressure of 9.61 atm, and a 6.65 L bulb containing oxygen gas

Contact [7]

Answer : The final pressure in the system is 4.22 atm.

Explanation :

First we have to calculate the moles of methane.

$PV=n_1RT$

where,

P = pressure of gas = 9.61 atm

V = volume of gas = 3.06 L

T = temperature of gas = T

$n_1$ = number of moles of methane gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$(9.61atm)\times (3.06L)=n_1\times RT$

$n_1=\frac{29.4}{RT}$

Now we have to calculate the moles of oxygen gas.

$PV=n_2RT$

where,

P = pressure of gas = 1.75 atm

V = volume of gas = 6.65 L

T = temperature of gas = T

$n_2$ = number of moles of oxygen gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$(1.75atm)\times (6.65L)=n_2\times RT$

$n_2=\frac{11.6}{RT}$

Now we have to determine the final pressure in the system after mixing the gases.

$P_{total}=(n_1+n_2)\times \frac{RT}{V_{total}}$

where,

$P_{total}$ = final pressure of gas = ?

$V_{total}$ = final volume of gas = (3.06 + 6.65)L = 9.71 L

T = temperature of gas = T

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$P_{total}=(\frac{29.4}{RT}+\frac{11.6}{RT})\times \frac{RT}{9.71L}$

$P_{total}=4.22atm$

Therefore, the final pressure in the system is 4.22 atm.

4 0

3 years ago

Select all that apply which of the following actions are permitted in balancing a chemical equation?

Annette [7]

When all coefficients are multiplied by a single factor, The following actions are allowed while balancing a chemical equation: adding coefficients in front of reactant and product formulations.

<h3>How can chemical equations maintain balance?</h3>

Equal numbers and types of each atom appear on both sides of balanced chemical equations . Coefficients in a balanced equation must be the simplest whole number ratio. Chemical processes always retain mass.

<h3>What is a simple chemical equation?</h3>

A chemical equation is a symbol- and formula-based symbolic representation of a chemical reaction, with the reactant entities supplied on the left side and the product entities given on the right.

To know more about chemical equation visit :

brainly.com/question/28294176

#SPJ4

8 0

2 years ago