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PolarNik [594]
3 years ago
12

Consider the following time series: t12345 6 11 9 14 15 a. Construct a time series plot. What type of pattern exists in the data

Mathematics
1 answer:
Anestetic [448]3 years ago
4 0

Answer:

Kindly check explanation and attached picture

Step-by-step explanation:

Given the time-series data:

Time (x) : 1 - - 2 - - 3 - - - 4 - - - 5

Data (yt) :6 - - 11 - - 9 - - 14 - - 15

The pattern which exists within the data is a linear pattern which could be inferred through the observable decrement and Incremental change in the y values at a steady or constant rate with time. The second attachment shows the linear trend line of the data.

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Help plz ASAP for 20pts
Paul [167]

Answer:

Not sure if this is correct but this is what I found.

area of sector=74.84

radius = 8

angle of sector=?

74.84=1/2×8²×angle of sector

74.84=32 × angle of sector

74.84/32= angle of sector

2.33875=angle of sector

Step-by-step explanation:

Sorry if it is incorrect.

4 0
3 years ago
51 and 53 HELP PLS!!!!!!!
Gelneren [198K]
Hi!
Answers:

51. w=9/4

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3 years ago
The radius of a circle is 11.7 in. Find the circumference \textit{to the nearest tenth}to the nearest tenth.
hjlf

Answer:

73.5

Step-by-step explanation:

circumference = 2πr , where r = radius

given radius = 11.7 so r = 11.7

C = 2πr

==> plug in r = 11.7

C = 2π(11.7)

==> multiply 2 and 11.7

C = 23.4π

==> multipl 23.4 and π

C = 73.5 ( rounded to the nearest tenth )

7 0
2 years ago
Read 2 more answers
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crimeas [40]

Answer:

W = 76m

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Step-by-step explanation:

5 0
3 years ago
Work out the volume of the shape​
pashok25 [27]

Answer:

\large\boxed{V=\dfrac{1,421\pi}{3}\ cm^3}

Step-by-step explanation:

We have the cone and the half-sphere.

The formula of a volume of a cone:

V_c=\dfrac{1}{3}\pi r^2H

r - radius

H - height

We have r = 7cm and H = (22-7)cm=15cm. Substitute:

V_c=\dfrac{1}{3}\pi(7^2)(15)=\dfrac{1}{3}\pi(49)(15)=\dfrac{735\pi}{3}\ cm^3

The formula of a volume of a sphere:

V_s=\dfrac{4}{3}\pi R^3

R - radius

Therefore the formula of a volume of a half-sphere:

V_{hs}=\dfrac{1}{2}\cdot\dfrac{4}{3}\pi R^3=\dfrac{2}{3}\pi R^3

We have R = 7cm. Substitute:

V_{hs}=\dfrac{2}{3}\pi(7^3)=\dfrac{2}{3}\pi(343)=\dfrac{686\pi}{3}\ cm^3

The volume of the given shape:

V=V_c+V_{hs}

Substitute:

V=\dfrac{735\pi}{3}+\dfrac{686\pi}{3}=\dfrac{1,421\pi}{3}\ cm^3

7 0
3 years ago
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