Ask question

Ask question

All categories

tino4ka555 [31]

3 years ago

10

Maya bought 3 CDs that were each the same price. Including sales tax, she paid a total of $ 47.70 . Each CD had a tax of $ 1.10

. What was the price of each CD before tax? $

1 answer:

Leni [432]3 years ago

5 0

47.70- 3.30=44.40

44.40/ 3=14.80

each cd cost 14.80

You might be interested in

Please answer i will give brainliest and extra points!

pav-90 [236]

Answer:

Esther's is more expensive

Step-by-step explanation:

2 dollars per soda

Brainly plss

4 0

3 years ago

What is 7 plus the sum of m and -17

olasank [31]

Answer:

m - 10

Step-by-step explanation:

7 plus = 7 +

The sum of m and -17 = m + (-17)

7 + (m + -17)

We can get rid of the parentheses

7 + m + -17

Combine like terms

7 + -17 = -10

m + -10

Get rid of the addition sign

m - 10

6 0

3 years ago

The probability of spinning a 4 on a spinner is 0.125.If you spun 150 times approximately how many times would the spinner land

Ksivusya [100]

Answer:

19

Step-by-step explanation:

To calculate this, all we need to do is 150 * 0.125 ≈ 18.75 which rounds to 19. We round to the nearest integer because you can't land on the 4 18.75 times.

6 0

3 years ago

Read 2 more answers

Plz help me!!!!!!!!!

Over [174]

Answer: $\bold{\dfrac{4\pm \sqrt{6}}{2}}$

<u>Step-by-step explanation:</u>

$\dfrac{3}{y-2}-2=\dfrac{1}{y-1}\\\\\\\text{Multiply by the LCD (y-2)(y-1) to clear the denominator:}\\\\\dfrac{3}{y-2}(y-2)(y-1)-2(y-2)(y-1)=\dfrac{1}{y-1}(y-2)(y-1)\\\\\\3(y-1)-2(y-2)(y-1)=1(y-2)\\\\3y-3-2(y^2-3y+2)=y-2\\\\3y-3-2y^2+6y-4=y-2\\\\-2y^2+9y-7=y-2\\\\0=2y^2-8y+5\quad \rightarrow \quad a=2,\ b=-8,\ c=5\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-8)\pm \sqrt{(-8)^2-4(2)(5)}}{2(2)}\\\\\\.\ =\dfrac{8\pm \sqrt{64-40}}{2(2)}$

$.\ =\dfrac{8\pm \sqrt{24}}{2(2)}\\\\\\.\ =\dfrac{8\pm 2\sqrt{6}}{2(2)}\\\\\\.\ =\dfrac{4\pm \sqrt{6}}{2}$

7 0

3 years ago

Given z=f(x,y),x=x(u,v),y=y(u,v), with x(4,1)=5 and y(4,1)=2, calculate zv(4,1) in terms of some of the values given in the tabl

Yuliya22 [10]

$z=f(x(u,v),y(u,v))\implies z_v=f_xx_v+f_yy_v$

$z_v(4,1)=f_x(5)x_v(4,1)+f_y(2)y_v(4,1)$

No table = incomplete answer

3 0

3 years ago