The question is incomplete and the complete question is
Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.
Answer:
AABb or AaBB
Explanation:
We know that,
aabb genotype - 6 cm
AABB genotype- 16-cm
To calculate the length of earlobe contributed by each allele in a genotype is :
1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)
2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)
Now to have the earlobe to be 13.5 cm long then the genotype must be
13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B
Therefore, the genotype will be-either AABb or AaBB
1.Fish gills are organs that allow fish to breathe underwater. Most fish exchange gases like oxygen and carbon dioxide using gills either on side of the pharynx.
2.Gills are branching organs located on the side of fish heads that have many, many small blood vessels called capillaries.
3.The colour is red
4. A Gill filaments project from each arc between the dorsal upper and ventral lower surfaces of the filaments.
Answer:
The active smokers and those getting exposed, that is, passive smokers are at enhanced threat of bacterial infections. Getting exposed to tobacco smoke enhances vulnerability to respiratory tract infections, comprising pneumonia, tuberculosis, and Legionnaires disease.
Smoking compromises the anti-bacterial activities of leukocytes incorporating monocytes, neutrophils, B cells, and T cells, thus, demonstrating the mechanism for enhanced risk of infections.
That would be temperature. (:
Hope this helps!
The answer is c gametophyte
