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3 years ago

Question 11 (5 points)

Chemistry

1 answer:

kolezko [41]3 years ago

3 0

Answer: Prince Shotoku's Constitution

Explanation:

Japanese schools were modeled after the Seventeen Article Constitution also known as Prince Shotoku's Constitution as he was the progenitor of the text.

The document which was based on the Confucian and Buddhist values, was issued in 604 CE when Prince Shotoku was regent and was meant to give support to the notion of a centralized state where people were ruled by one person.

It also called for officials of the nation to be elected not because of their family name but based on their ability to do the required work amongst other things.

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Will mark Brainlest ( molecular weight of ammonium sulphate)<br>step by step

Bond [772]

Answer:

132 amu

Explanation:

ammonium sulphate is $(NH_4)_{2} SO_4$

to calculate molecular weight we need

atomic weight of the element of the compound

here ammonium sulphate is formed by two elements

2 nitrogen , 8 hydrogen , 1 sulphur amd 4 oxygen

atonomic number of nirogen is 14 , hydrogen is 1 , sulphur has 32 and oxygen has 16

so lets calculate molecular weight of ammonium sulphate

2*14 + 8*1 + 1*32 + 4*16

28 + 8 + 32 + 64

132 amu

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3 years ago

1. What are some similarities between the dogs pictured? What are some differences?

kogti [31]

1. Some differences are that they are all different kinds of dogs

2. Small dogs and big dogs

That is all I can answer

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3 years ago

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How many milliliters of milk are in a 1.000-<br> gallon jug?

mart [117]

Answer:

3.785e+6

Explanation:

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4 years ago

4.All of these are types of radioactive decay except

Schach [20]

The answer is D. Delta I believe
Good luck let me know if it’s right :)

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3 years ago

In an experiment, 8.50 g of methane, CH4, was reacted with 15.9 g of oxygen gas to produce carbon dioxide and water. Determine t

exis [7]

Answer:

89.3 %

Explanation:

M(CH4) = 12+ 4*1 = 16 g/mol

M(O2) = 2*16 = 32 g/mol

M(CO2) = 12 + 2*16 = 44 g/mol

8.50 g * 1 mol/16 g = 0.5313 mol CH4

15.9 g * 1 mol/32 g = 0.4969 mol O2

9.77 g * 1 mol/44 g = 0.2220 mol CO2

1) CH4 + 2O2 -----> CO2 + 2H2O

from reaction 1 mol 2 mol

given 0.5313 mol (0.4969 mol)

1 mol CH4 --- 2 mol O2

0.5313 mol CH4 --- x mol O2

x= 2*0.5313 = 1.0626 mol O2

We can see that for given amount of CH4 we do not have enough O2, so O2 is a limiting reactant.

2) CH4 + 2O2 -----> CO2 + 2H2O

from reaction 2 mol 1 mol

given 0.4969 mol x mol

x = 0.4969*1/2 = 0.2485 mol CO2 theoretical yield

Practical yield CO2 = 0.2220 mol

Theoretical yield CO2 = 0.2485 mol

% yield = (0.2220/0.2485)*100% = 89.3 %

7 0

4 years ago