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Aleksandr [31]
3 years ago
11

Convert 5.67 L into mL. 0 56.7 mL O 567 ml O 5,670 mL O 5.67 mL

Chemistry
2 answers:
Lelechka [254]3 years ago
6 0
Answer: C. 5,670 mL
soldi70 [24.7K]3 years ago
5 0
C. 5670 mL

1 liter is 1000 ml so 5.67 * 1000 is 5670
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eimsori [14]
<h2>Question 1:</h2><h3>32g + <u><em>56g</em></u> --> 88g</h3>

This one's just a simple math problem. Do 88 - 32, which is 56. You can also find the same answer by looking for the atomic mass of iron (Fe), which rounds up to 56.


<h2>Question 2:</h2><h3>This equation is <u><em>balanced</em></u>.</h3>

On the left side, there is 2 Nitrogen (because of the subscript), and 6 Hydrogen (3 x 2 = 6). On the right side, there is 2 Nitrogen (because of the coefficient), and 6 Hydrogen. (2 x 3 again) There are 2 Nitrogen and 6 Hydrogen on each side, therefore the equation is balanced.


<h2>Question 3:</h2><h3>This equation is <em><u>unbalanced.</u></em></h3>

On the left side, there are 2 Nitrogen (N) and 2 Hydrogen (H). On the right side, there is 1 Nitrogen and 6 Hydrogen. There are 2 Nitrogen and 2 Hydrogen on one side, while the other only has 1 Nitrogen and 6 Hydrogen. Therefore the equation is unbalanced.


<h2>Question 4:</h2><h3>This equation is <em><u>balanced.</u></em></h3>

On the left side, there are 2 Chromium (Cr) and 6 Chlorine (Cl). On the right side, there are 2 Chromium and 6 Chlorine. There are 2 Chromium and 6 Chlorine on each side, therefore the equation in balanced.

~~~~~~~~~~~~~~~~~~~~~~~

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6 0
4 years ago
I need help on this one for an exam real quick please​
gogolik [260]

Answer:

See Explanation

Explanation:

In the first case, when potassium iodide is added to an aqueous bromine solution, a chemical reaction occurs as follows;

Br2(l) + 2 KI(aq) = 2 KBr(aq) + I2(l)

This reaction produces iodine solution which is brown in colour.

Secondly, when potassium iodide is added to aqueous chlorine solution, the following reaction occurs;

2KI(aq) + Cl2(l)→ 2KCl(aq) + I2 (l)

This reaction also yields iodine solution which is brown in colour.

KI(aq) + I2(l) -------->K^+(aq) + I3^-(aq)

The  I3^-(aq) solution appears brown at high concentrations.

8 0
3 years ago
2.<br> Name the following compounds:<br> a. Rb20
olya-2409 [2.1K]

Answer:

Rubidium oxide

Explanation:

7 0
4 years ago
Read 2 more answers
The equilibrium constant for the reaction
Hitman42 [59]

The question is incomplete, here is the complete question:

The equilibrium constant for the reaction

N₂O₄(g)⇌2NO₂ at 2°C is Kc = 2.0

If each yellow sphere represents 1 mol of N₂O₄(g) and each gray sphere 1 mol of NO₂ which of the following 1.0 L containers represents the equilibrium mixture at 2°C?

The image is attached below.

<u>Answer:</u> The system which represents the equilibrium having value of K_c=2.0 is system (b)

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c

For a general chemical reaction:

aA+bB\rightarrow cC+dD

The expression for K_{c} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

For the given chemical equation:

N_2O_4(g)\rightleftharpoons 2NO_2

The expression of K_c for above equation follows:

K_c=\frac{[NO_2]^2}{[N_2O_4]}      .......(1)

We are given:

Volume of the container = 1.0 L

Value of K_c = 2.0

Molarity of the substance is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume}}

For the given images:

  • <u>For a:</u>

Number of Gray spheres = 8 moles

Number of yellow spheres = 4 moles

Putting values in expression 1, we get:

K_c=\frac{(8/1)^2}{(4/1)}\\\\K_c=16

  • <u>For b:</u>

Number of Gray spheres = 4 moles

Number of yellow spheres = 8 moles

Putting values in expression 1, we get:

K_c=\frac{(4/1)^2}{(8/1)}\\\\K_c=2

  • <u>For c:</u>

Number of Gray spheres = 6 moles

Number of yellow spheres = 6 moles

Putting values in expression 1, we get:

K_c=\frac{(6/1)^2}{(6/1)}\\\\K_c=6

  • <u>For d:</u>

Number of Gray spheres = 2 moles

Number of yellow spheres = 8 moles

Putting values in expression 1, we get:

K_c=\frac{(2/1)^2}{(8/1)}\\\\K_c=\frac{1}{2}

Hence, the system which represents the equilibrium having value of K_c=2.0 is system (b)

3 0
4 years ago
Which procedure confirms the presence of F ions, CI ions, Br ions, I ions?
nexus9112 [7]

Answer:

F-, no precipitate. Cl-, white precipitate. Br-, very pale cream precipitate. I-, very pale yellow precipitate.

Explanation:

5 0
3 years ago
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