Answer:
12 is the answer thanks for asking in
The manager already hired 9 people. Let
be the number of people he still can hire. Since these people will add to the 9 he already hired, when the hiring campaign will be over he will have hired
people. We know that he can't hire more than 14 people, so the number of people hired must be less than or equal to 14:

If we subtract 9 from both sides, we have

so, the manager can hire at most 5 other people
Less, 12 x 3/4 is 9 as you take 12/4 which is 3 times 3, which gives you 9
yes because 6 x 2.49=14.49 and that's less than 20 so you'll have a little over 5 dollars to spare.
Hey,
2x^2 + 3root5x + 5
Here the product=10
And,sum=3root5
=>2x^2+2root5x+root5x+5
=>2x(x+root5)+ root5(x+root5)
=>(2x+root5)(x+root 5)