-- You and your partner both get the same job to do:
Each of you gets a pallet of bricks, and you have to
put the bricks up on the bed of a truck, by hand.
Both pallets have the same number of bricks.
The pallet is way too heavy to lift, so you both cut the bands
that hold the bricks, and you lift the bricks from the pallet onto
the truck, by hand, two or three or four bricks at a time.
-- You get your pallet of bricks onto the truck in 45 minutes.
-- Your partner gets his pallet of bricks onto the truck in 3 days.
-- Work = (force) times (distance).
You and your partner both lifted the same amount of weight
up to the same height. You both did the same amount of work.
-- Power = (work done) divided by (time it takes to do the work) .
Your partner took roughly 96 times as long as you took
to do the same amount of work.
You did it faster. He did it slower.
You produced more power. He produced less power.
The distance covered is 1000 m
Explanation:
The rocket is moving by uniformly accelerated motion, so we can find the distance it covers by using the following suvat equation:

where
s is the distance covered
v is the final velocity
t is the time
a is the acceleration
For the rocket in this problem, we have:
v = 445 m/s is the final velocity
is the acceleration
t = 4.50 s is the time
Substituting, we find the distance covered:

Learn more about accelerated motion:
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Answer:
2.58 x 10⁸ m/s
Explanation:
Time dilation fomula will be applicable here, which is given below.
t = \frac{T}{\left ( 1-\frac{v^2}{c^2} \right )^\frac{1}{2}}
Where T is dilated time or time observed by clock in motion , t is stationary time , v is velocity of clock in motion and c is velocity of light .
c is 3 times 10⁸ ms⁻¹ , T is 7.24 h , t is 3.69 h. Put these values in the formula
7.24 = \frac{3.69}{\left ( 1-\frac{v^2}{c^2} \right )^\frac{1}{2}}\\
\frac{v^2}{c^2}=0.744\\\\
v=2.58\times 10^8
Answer:
0
Explanation:
the momentum will always be 0 when it is at rest because the object isnt moving!
Hope this helped!
Answer:
6 amps
Explanation:by Kirchhoff's loop rule the current at any point in the loop must be equal or charge would be building up. The current at the ammeter is equally to the total current through the sun of the paths in parallel which it is in series with