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BlackZzzverrR [31]
2 years ago
12

A 432 g sample of 60/27Co has a decay constant of 4.14 x 10-9 s-1. How long will it take before only 1/3 of the original sample

remains?
Physics
1 answer:
Musya8 [376]2 years ago
7 0

Answer:

remain 1s60

Explanation:

I took away sample

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A certain shade of blue has a frequency of 7.15 × 1014 hz. what is the energy of exactly one photon of this light?
Ket [755]
The energy carried by a single photon of frequency f is given by:
E=hf
where h=6.6 \cdot 10^{-34} m^2 kg s^{-1} is the Planck constant. In our problem, the frequency of the photon is f=7.15 \cdot 10^{14}Hz, and by using these numbers we can find the energy of the photon:
E=(6.6\cdot 10^{-34}m^2 kg s^{-1})(7.15 \cdot 10^{14}Hz)=4.7 \cdot 10^{-19}J
4 0
3 years ago
Express the kinetic energy K in terms of the potential energy U.<br><br><br> K=GMm/2R
max2010maxim [7]

Answer:

K = -½U

Explanation:

From Newton's law of gravitation, the formula for gravitational potential energy is;

U = -GMm/R

Where,

G is gravitational constant

M and m are the two masses exerting the forces

R is the distance between the two objects

Now, in the question, we are given that kinetic energy is;

K = GMm/2R

Re-rranging, we have;

K = ½(GMm/R)

Comparing the equation of kinetic energy to that of potential energy, we can derive that gravitational kinetic energy can be expressed in terms of potential energy as;

K = -½U

7 0
3 years ago
A horizontal force in used to pull a 5 kilogram cart at a constant speed of 5 meters per second across the floor as shown in the
ddd [48]

A cart is pulled by horizontal force such that it moves with constant velocity

So here since velocity is constant we can say that its acceleration will be ZERO

now here for zero acceleration we can say

F_{net} = 0

So here we will have

F_{net} = F_{ap} - F_f = 0

here we know that

F_f = 10 N

so we will have

F_{ap} - 10 = 0

F_{ap} = 10 N

so here applied force on handle will be

<em>b. 10 N</em>

5 0
3 years ago
Janet wants to find the spring constant of a given spring, so she hangs the spring vertically and attaches a 0.50 kg mass to the
frez [133]
Given: Mass m = 0.50 Kg;     Force = Weight = mg   F = (0.50 Kg)(9.8 m/s²)

                                               F = 4.9 N      

Displacement  x = 3.0 cm   convert to meter   x = 0.03 m

Required: Spring constant  k = "

Formula:  F = kx

                k = F/x

                k = 4.9 N/0.03 m

                k = 163.33 N/m


                    

                                                                      
3 0
3 years ago
I need help on 6 7,8 and 9
pantera1 [17]
6. F- DNA
7. C
8. G
9. D
I believe these are correct, hope this helps. 
7 0
3 years ago
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