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djverab [1.8K]
4 years ago
5

Using a simple machine, a student is able to lift a 500N weight by applying only 100N. What is the mechanical advantage of the s

imple machine? A) 0.2 B) 1 C) 5 D) 50000
Physics
1 answer:
Vanyuwa [196]4 years ago
4 0

Answer:

The answer is 5

Explanation:

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Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2ax. The problem requires so
lisabon 2012 [21]

As per kinematics equation we are given that

v^2 = v_o^2 + 2ax

now we are given that

a = 2.55 m/s^2

v_0 = 21.8 m/s

v = 0

now we need to find x

from above equation we have

0^2 = 21.8^2 + 2(2.55)x

0 = 475.24 + 5.1 x

x = 93.2 m

so it will cover a distance of 93.2 m

7 0
4 years ago
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Why is it necessary to centrifuge out any precipitate formed in the unknown solution and continue testing the remaining unknown
jonny [76]

Answer:

Precipitation is the formation of a solid from a solution. It is necessary to centrifuge the precipitate to exert sufficient forces of gravity to bring the solid particles in the solution to come together and settle

Explanation:

When you centrifuge precipitate it enables the nucleation to form.

Centrifuging the precipitate helps in determining whether a certain element is present in a solution or not.

5 0
3 years ago
An object's position in a given coordinate system is described by the vector r = t2 i - (3t + 3) j. Assume the object moves with
Ipatiy [6.2K]

Answer:

The object´s displacement vector is Δr =  8i - 6 j  

Explanation:

Hi there!

The position vector is given by the following function:

r = t²i - (3t + 3) j

Let´s find the position of the object at time t1 and t2:

At t1 = 1 s:

r1 = (1)² i - (3 · (1) + 3 )j

r1 = 1 i - 6 j

At t2 = 3 s:

r2 = (3)² i - (3 · (3) + 3) j

r2 = 9 i - 12 j

The displacement is calculated as follows:

displacement = Δr = final position - initial position = r2 - r1

r2 - r1 = 9 i - 12 j - (1 i - 6 j)

r2 - r1 = 9 i - 12 j - 1 i + 6 j

r2 - r1 = 8 i - 6 j

The object´s displacement vector is Δr =  8i - 6 j  

8 0
3 years ago
After six half-lives, what percentage of a radioactive sample will remain?
tatiyna
Well at the fourth half-life it would be 6.25% so if you continue calculating the answer would be B.
4 0
4 years ago
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Whihc radiations treat cancer is it a)beta b)alpha c)gamma d) all
Lena [83]

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Treatment.

Basically according to the theory, GAMMA rays are used to treat the cancer.

c.) GAMMA RADIATIONS

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4 years ago
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