Answer:
Price > 100$
Price > 150$
Step-by-step explanation:
Let us assume that x% off of price y$ is better than x$ off.
Hence, 
Hence, y > 100
Therefore, when the price is more than 100$, then only x% off on the price is better than x$. (Answer)
Again, assume that 20% off on price y$ is better than 30$ off.
Hence, 
⇒ y > 150$
Therefore, when the price is more than 150$, then only 20% of on the price is better than 30$ off. (Answer)
Answer:
To find the sum of a positive and a negative integer, take the absolute value of each integer and then subtract these values. The result takes the sign of the integer with the larger absolute value. The sum of any integer and its opposite is equal to zero.
Writing this problem in symbols instead of in words greatly simplifies it:
(2 2/3) * (1 1/5) * (1 1/2)
Write each quantity (inside each set of parentheses) as an improper fraction:
(8/3) * (6/5) * (3/2)
Now multiply the numerators thru: 8*6*3 / 3*5*2
Notice that we can reduce this by dividing the 8 by the 2 and dividing the 6 by the 3: 4*3*3 36
---------- = -----------
5 5
G=5(z+s)
70=5(z+6)
70=5z+30
40=5z
z=8
Zane is 8
2a+3c=22.00 ......equation 1
a+4c=18.50 =>2a+8c=37.00 .....equation 2
subtract equation one from equation two:
5c=37-22=15
c=3
a+4*3=18.50 =>a=6.50
for the Hu family: 3*6.50+1*3.00=22.50 dollars
