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3 years ago

Explain in detail what specific factors affect the momentum of a bicycle going down hill.

Physics

1 answer:

Crazy boy [7]3 years ago

4 0

Mass and velocity are the two terms which affect momentum of a bicycle going hill down.

Explanation:

As we know that Momentum describes the motion of an object. It is the combination of the objects mass and velocity.

So, obviously with no doubt mass and velocity are the two terms which affect momentum.

Momentum(p) = Mass(m) * Velocity(v)

The momentum also depends upon the mass and speed of the object.

More the mass of the object more is the momentum.

Depending upon the gravity and bicycle's motion speed momentum varies.

Bicycle moves faster the down hill if it moves with some speed as it has lesser mass the momentum also will be less.

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John is carrying a shovelful of snow. The center of mass of the 3.00 kg of snow he is holding is 15.0 cm from the end of the sho

Andru [333]

Answer:

James is correct here as the force of hand pushing upwards is always more than the force of hand pushing down

Explanation:

Here we know that one hand is pushing up at some distance midway while other hand is balancing the weight by applying a force downwards

so here we can say

Upwards force = downwards Force + weight of snow

while if we find the other force which is acting downwards

then for that force we can say that net torque must be balanced

so here we have

$F_{down} L_1 = W_{snow} L_2$

so here we have

$F_{down} = \frac{L_2}{L_1} (W_{snow})$

so here we can say that upward force by which we push up is always more than the downwards force

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3 years ago

The speed that light travels :

OLga [1]

I think it might be C.

4 0

2 years ago

Read 2 more answers

A worker does 25 J of work lifting a bucket, then sets the bucket back down in the same place. What is the total net work done o

Vera_Pavlovna [14]

Answer:

0 J

Explanation:

As work is force times displacement, if no displacement occurs, no work occurs.

5 0

2 years ago

If the coefficient of static friction is 0.357, and the same ladder makes a 58.0° angle with respect to the horizontal, how far

zavuch27 [327]

Answer: d= 0.57* l

Explanation:

We need to check that before ladder slips the length of ladder the painter can climb.

So we need to satisfy the equilibrium conditions.

So for ∑Fx=0, ∑Fy=0 and ∑M=0

We have,

At the base of ladder, two components N₁ acting vertical and f₁ acting horizontal

At the top of ladder, N₂ acting horizontal

And Between somewhere we have the weight of painter acting downward equal to= mg

So, we have N₁=mg

and also mg*d*cosФ= N₂*l*sin∅

So,

d= $\frac{N2}{mg}*l$ * tan∅

Also, we have f₁=N₂

As f₁= чN₁

So f₁= 0.357 * 69.1 * 9.8

f₁= 241.75

Putting in d equation, we have

d= $\frac{241.75}{69.1*9.8} *l$ * tan 58

d= 0.57* l

So painter can be along the 57% of length before the ladder begins to slip

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3 years ago

Read 2 more answers

If Pressure = 1000 Pa and Area = 0.2 m square, then Force

Maksim231197 [3]

Here

Pressure=1000Pa

Area=0.2m Square

Force=?

Now,,

Pressure =force / Area

1000=force/0.2

force=1000/0.2

Therefore,Force=5000N

3 0

2 years ago