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ArbitrLikvidat [17]
3 years ago
12

Explain in detail what specific factors affect the momentum of a bicycle going down hill.

Physics
1 answer:
Crazy boy [7]3 years ago
4 0

Mass and velocity are the two terms which affect momentum of a bicycle going hill down.

Explanation:

As we know that Momentum describes the motion of an object. It is the combination of the objects mass and velocity.

So, obviously with no doubt mass and velocity are the two terms which affect momentum.

Momentum(p) = Mass(m) * Velocity(v)

The momentum also depends upon the mass and speed of the object.

More the mass of the object more is the momentum.

Depending upon the gravity and bicycle's motion speed momentum varies.

Bicycle moves faster the down hill if it moves with some speed as it has lesser mass the momentum also will be less.

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3 years ago
Three forces with magnitudes of 95 pounds, 75 pounds, and 146 pounds act on an object at angles 100°, 200°, and 300°, respective
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Answer:

Explanation:

We shall represent all the forces in vector form .

Force of 95 pounds

F₁ = 95cos100 i + 95sin100j

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force of 75 pounds

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= -70.47 i - 25.65 j

force of 146 pounds

F₃ = 146cos300 i + 146sin300j

= 73i -126.44 j

Resultant force

R = F₁+ F₂ + F₃

=  -16.5 i +93.55 j  -70.47 i - 25.65 j +73i -126.44 j

= -13.97 i - 58.54 j

Magnitude of R = √ ( 13.97² + 58.54² )

= 60.18

If Ф be angle of resultant with  axis

tanФ = - 58.54 / -13.97

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A 1470-kilogram truck moving with a speed of 27.0 m/s runs into the rear end of a 1010-kilogram stationary car. If the collision
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Answer:

\Delta KE = 218.375\ kJ

Explanation:

Given,

Mass of the truck, M =  1470 Kg

initial speed of the truck, u = 27 m/s

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initial speed of car, u' = 0 m/s

Final speed, V = ?

Using conservation of momentum

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V = 16\ m/s

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\Delta KE = \dfrac{1}{2} Mu^2 - \dfrac{1}{2}(M+m)V^2

\Delta KE = \dfrac{1}{2}\times 1470\times 27^2 - \dfrac{1}{2}\times (1470 + 1010)\times 16^2

\Delta KE = 218.375\ kJ

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