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Stells [14]
3 years ago
15

Sharks are generally negatively buoyant; the upward buoyant force is less than the weight force. This is one reason sharks tend

to swim continuously; water moving past their fins causes a lift force that keeps sharks from sinking. A 92 kg bull shark has a density of 1040 kg/m3. What lift force must the shark's fins provide if the shark is swimming in seawater? Bull sharks often swim into freshwater rivers. What lift force is required in a river?
Physics
1 answer:
Tresset [83]3 years ago
6 0

Answer:

8.67807 N

34.7123 N

Explanation:

m = Mass of shark = 92 kg

\rho_{se} = Density of seawater = 1030 kg/m³

\rho_{f} = Density of freshwater = 1000 kg/m³

\rho_{sh} = Density of shark = 1040 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

Net force on the fin is (seawater)

F_n=mg-V_s\rho_{se}g\\\Rightarrow F_n=mg-\frac{m}{\rho_{sh}}\rho_{se}g\\\Rightarrow F_n=92\times 9.81-\frac{92}{1040}\times 1030\times 9.81\\\Rightarrow F_n=8.67807\ N

The lift force required in seawater is 8.67807 N

Net force on the fin is (freshwater)

F_n=mg-V_s\rho_{f}g\\\Rightarrow F_n=mg-\frac{m}{\rho_{sh}}\rho_{f}g\\\Rightarrow F_n=92\times 9.81-\frac{92}{1040}\times 1000\times 9.81\\\Rightarrow F_n=34.7123\ N

The lift force required in a river is 34.7123 N

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Answer:

Displacement of Mr. Llama: Option D. 0 miles.

Explanation:

The magnitude of the displacement of an object is equal to the distance between its final position and its initial position. In other words, as long as the initial and final positions of the object stay unchanged, the path that this object took will not affect its displacement.

For Mr. Llama:

  • Final position: Mr. Llama's house;
  • Initial position: Mr. Llama's house.

The distance between the final and initial position of Mr. Llama is equal to zero. As a result, the magnitude of Mr. Llama's displacement in the entire process will also be equal to zero.

7 0
3 years ago
What is the current I(3τ), that is, the current after three time constants have passed? The current in the circuit will approach
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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

I(\tau)=0.051 A

b

I(3 \tau)=0.076 A

c

I_c= 0.08 A

Explanation:

From the question we are told that

                I(t) = \frac{e}{R}(1-e^{\frac{t}{\tau} }) ; \ Where \ \tau = L/R

From the question we are told to find I(\tau) when t=0  equals the time constant (\tau)

That is to obtain I(\tau).This  is mathematically represented as

                   I(\tau = t)  = \frac{\epsilon}{R} (1- e^{-\frac{\tau}{\tau} })

             Substituting 12 V for \epsilon and 150Ω for R

                     I(\tau) = \frac{12}{150} (1- e^{-1})

                            =0.051 A

From the question we are told to find I(3 \tau) when t=0  equals the 3 times the  time constant (\tau)

That is to obtain I(3\tau).This  is mathematically represented as

                 I(\tau = t)  = \frac{\epsilon}{R} (1- e^{-\frac{3\tau}{\tau} })

                  I(\tau) = \frac{12}{150} (1- e^{-3})

                        =0.076 A

As tends to infinity \frac{\infty}{\tau}  = \infty

So I_c would be mathematically evaluated as

               I_c=I(\infty) = \frac{12}{150} (1- e^{- \infty})

                   = \frac{12}{150}

                   = 0.08 A

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Answer:

a) "gravitation" is the force causing you to go down a waterslide

b) It is "fluid friction" as a solid object (our body) moves over a fluid (the water)

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d) fluid friction being the weakest friction, switching to sliding friction means a higher decrease in speed and therefore removing the water from a slide will decrease our speed

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Answer:

Answer below!!!!

Explanation:

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Hope I Helped!!!

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5 0
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