The period of the sound wave at the given frequency is determined as 0.00235 second.
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Period of the sound wave</h3>
The period of the sound wave at the given frequency is calculated as follows;
Period is reciprocal of frequency.
T = 1/f
T = 1/425
T = 0.00235 second
Thus, the period of the sound wave at the given frequency is determined as 0.00235 second.
Learn more about period here: brainly.com/question/10428039
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Their are two coefficients of friction, static and kinetic, regardless, they have basically the same formula:
u*N = F... aka
coefficient of friction*normal force = force of friction
Hope that helps!
Answer:
83.3 kHz
Explanation:
The frequency of a waveform is equal to the reciprocal of its period:

where
f is the frequency
T is the period
In this problem, we have

so, the frequency of the waveform is

And by converting into kiloHertz,

Answer:
The acceleration is 3.16x10¹⁷ m/s².
Explanation:
First, we need to find the magnitude of the Coulombs force (F):

<u>Where</u>:
K is the Coulomb constant = 9x10⁹ Nm²/C²
q₁ is the charge = 20x10⁻⁹ C
q₂ is the electron's charge = -1.6x10⁻¹⁹ C
d is the distance = 1.0 cm = 1.0x10⁻² m
Now, we can find the acceleration:

Therefore, the acceleration is 3.16x10¹⁷ m/s².
I hope it helps you!