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2 answers:
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Answer:
The ball traveled 0.827 m
Explanation:
Given;
distance between the metal plates of the room, d = 3.1 m
mass of the glass, m = 1.1g
charge on the glass, q = 4.7 nC
speed of the glass ball, v = 4.8 m/s
voltage of the ceiling, V = +3.0 x 10⁶ V
The repulsive force experienced by the ball when shot to the ceiling with positive voltage, can be calculated using Coulomb's law;
F = qV/d
|F| = (4.7 x 10⁻⁹ x 3 x 10⁶) / (3.1)
|F| = 4.548 x 10⁻³ N
F = - 4.548 x 10⁻³ N
The net horizontal force experienced by this ball is;
The work done between the ends of the plate is equal to product of the magnitude of net force on the ball and the distance traveled by the ball.
W = K.E
Therefore, the ball traveled 0.827 m
Answer:
4.55 x 10⁹m
Explanation:
Given parameters:
Mass of object 1 = 3.1 x 10⁵kg
Mass of object 2 = 6.5 x 10³kg
Gravitational force = 65N
Unknown:
Distance between them = ?
Solution:
To solve this problem, we use the expression below from the universal gravitational law;
Fg =
G = 6.67 x 10⁻¹¹
65 =
Distance = 4.55 x 10⁹m