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Alex_Xolod [135]
2 years ago
7

A 4-m long wire with a mass of 70 g is under tension. A transverse wave for which the frequency is 300 Hz, the wavelength is 0.6

m, and the amplitude is 6 mm is propagating on the wire. The maximum transverse acceleration of a point on a wire is closest to
Physics
1 answer:
slavikrds [6]2 years ago
7 0

Answer:5400 m/s^2

Explanation: In order to calculate the acceleration we have to use the centripetal form  of it given by:

a= v^2/R where v is the velocity and r the radius of the circular movement  which correspond to the maximum of amplitude of the transverse wave.

To calculate the velocity we know that v=ν*λ, where νand λ, are the frequency and wavelength of the wave, respectively. v=300*0.6=180 m/s

Finally we have:

a= (180 m/s)^2/6 m= 5400 m/s^2

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If the magnetic flux through a loop increases according to the relation; where , is in milliweber (mWb) and t is in seconds. Cal
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The magnitude of e.m.f induced in the loop when t = 2 s is 31 Volts.

<h3>emf induced in the loop</h3>

The magnitude of e.m.f induced in the loop is calculated as follows;

emf = dФ/dt

Ф = 6t² + 7t

dФ/dt = 12t + 7

at t = 2 seconds

emf = dФ/dt = 12(2) + 7 = 31 V

Thus,  the magnitude of e.m.f induced in the loop when t = 2 s is 31 Volts.

Learn more about emf here: brainly.com/question/24158806

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A projectile has an initial horizontal velocity of 34.0 M/s at the edge of a roof top. Find the horizontal and vertical componen
Sveta_85 [38]

Answer:

v_x=34 m/s

v_y=53.9\ m/s

Explanation:

<u>Horizontal Launch</u>

When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it eventually hits the ground.

The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

vx=v

The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:

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The horizontal component of the velocity is always the same:

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The vertical component at t=5.5 s is:

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v_y=53.9\ m/s

8 0
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A sample of chlorine has two naturally occurring isotopes. The isotope Cl-35 (mass 35.0 amu) makes up 75.8% of the sample, and t
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Answer:

M_{av}=35.521amu

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As in any sample you will have 75.8% of Cl-35 iosotopes and 24.3% of Cl-37 iosotopes you can get the average atomic mass as:

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4 0
2 years ago
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