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3 years ago

Evaluate 9!/6!3! A: 1 B: 84 C: 68

Mathematics

1 answer:

Anika [276]3 years ago

8 0

B, im hundred percent sure its right

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Which shows the correct substitution of the values a, b, and c from the equation 1 = –2x + 3x2 + 1 into the quadratic formula?

Alchen [17]

$1=-2x+3x^2+1\\\\3x^2-2x+1-1=0\\\\3x^2-2x=0\\\\\boxed{a=3;\ b=-2;\ c=0}$

6 0

2 years ago

Read 2 more answers

Solve for the value of b

OverLord2011 [107]

Answer:

Step-by-step explanation:

7b-2+3b+2=180

10b=180

b=18

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2 years ago

Solve by using substitution. Express your answer as an ordered pair.

romanna [79]

Answer:

(2,3)

Step-by-step explanation:

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1 year ago

An angle is 21 degree more than twice its complement find it

jekas [21]

Answer: 67°

Step-by-step explanation:

Complementary angle refers to the angle that when added together will be equal to 90°.

Let the measurement of the angle's complement be x.

Therefore, the angles are x and 2x + 21. Since it's a complementary angle, therefore,

x + 2x + 21 = 90

3x + 21 = 90

3x = 90 - 21

3x = 69

x = 69°/3

x = 23°

Therefore, the angle will be:

= 2x + 21

= 2(23°) + 21°

= 46° + 21°

= 67°

The angle is 67°.

5 0

2 years ago

7.<br>(-3x³)(-2x³y⁴z)(-3z²)÷(4x³z)(-3yz) (-3xyz)

serg [7]

Answer:

$-\frac{x^2y^2}{2}$

Step-by-step explanation:

We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :

Remove the parenthesis to make it easier to read :

$\frac{-3x^3 *2x^3y^4z *3z^2}{4x^3z*3yz*3xyz}$

Multiply the numerators :

$\frac{-18x^6y^4z^3}{4*3*3x^3yyzzz}$

Multiply the denominators :

$\frac{-18x^6y^4z^3}{36x^4y^2z^3}$

Apply the negative rule :

$-\frac{18x^6y^4z^3}{36x^4y^2z^3}$

Cancel the common factor which is 18 :

$-\frac{x^6y^4z^3}{2x^4y^2z^3}$

Apply the addition exponent rule :

$\frac{y^4z^3x^{6-4} }{2y^2z^3}$

Subtract :

$\frac{x^2y^4z^3 }{2y^2z^3}$

Apply the rule for y :

$\frac{x^2y^{4-2} z^3 }{2z^3}$

Subtract :

$\frac{x^2y^2z^3 }{2z^3}$

Cancel the common factor of z^3 :

$-\frac{x^2y^2}{2}$

5 0

2 years ago