Which book has kinetic energy?
2 answers:
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Answer:
0.04865 m
Explanation:
k = Spring Constant
m = Mass
d = Distance
g = Acceleration due to gravity = 9.81 m/s²
Angular frequency is given by
At equilibrium we have
The distance by which the spring stretches from its unstrained length is 0.04865 m
Answer: 313920
Explanation:First, we’re going to assume that the top of the circular plate surface is 2 meters under the water. Next, we will set up the axis system so that the origin of the axis system is at the center of the plate.
Finally, we will again split up the plate into n horizontal strips each of width Δy and we’ll choose a point y∗ from each strip. Attached to this is a sketch of the set up.
The water’s surface is shown at the top of the sketch. Below the water’s surface is the circular plate and a standard xy-axis system is superimposed on the circle with the center of the circle at the origin of the axis system. It is shown that the distance from the water’s surface and the top of the plate is 6 meters and the distance from the water’s surface to the x-axis (and hence the center of the plate) is 8 meters.
The depth below the water surface of each strip is,
di = 8 − yi
and that in turn gives us the pressure on the strip,
Pi =ρgdi = 9810 (8−yi)
The area of each strip is,
Ai = 2√4− (yi) 2Δy
The hydrostatic force on each strip is,
Fi = Pi Ai=9810 (8−yi) (2) √4−(yi)² Δy
The total force on the plate is found on the attached image.
Answer:
a) is the height where the rocket stops accelerating and its fuel is finished and starts decelerating while it still continues to move in the upward direction.
b) is speed of the rocket going when it stops accelerating.
c)
d)
e) Zero, since the average velocity is the net displacement per unit time and when the rocket strikes back the earth surface the net displacement is zero.
Explanation:
Given:
acceleration of rocket,
time for which the rocket accelerates,
<u>For the course of upward acceleration:</u>
using eq. of motion,
where:
initial velocity of the rocket at the launch
height the rocket travels just before its fuel finishes off
so,
a) is the height where the rocket stops accelerating and its fuel is finished and starts decelerating while it still continues to move in the upward direction.
<u>Now the velocity of the rocket just after the fuel is finished:</u>
b) is speed of the rocket going when it stops accelerating.
After the fuel is finished the rocket starts to decelerates. So, we find the height of the rocket before it begins to fall back towards the earth.
Now the additional height the rocket ascends before it begins to fall back on the earth after the fuel is consumed completely, at this point its instantaneous velocity is zero:
using equation of motion,
where:
acceleration due to gravity
final velocity of the rocket at the top height
c) So the total height at which the rocket gets:
d)
Time taken by the rocket to reach the top height after the fuel is over:
Now the time taken to fall from the total height:
Hence the total time taken by the rocket to strike back on the earth:
e)
Zero, since the average velocity is the net displacement per unit time and when the rocket strikes back the earth surface the net displacement is zero.