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2 years ago

7

If the velocity of an object changes from 15 m/s during a time interval of 4s what is the acceleration of the object

1 answer:

Fiesta28 [93]2 years ago

6 0

The acceleration of an object is defined as change in velocity divided by change in time, that is,
Acceleration = change in velocity / change in time
In the question given above,
Change in velocity = 15
Change in time = 4
Acceleration = 15 /4 = 3.75
Therefore, acceleration = 3.8 m/s^2.

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Wires 1, 2, and 3 each have current moving through them to the right. I1 = 10 A, I2 = 5 A, and I3 = 8 A. Wire 2 is 15 cm long an

Rudik [331]

Answer:

F_2 = 20 x 10⁻⁶ N

Explanation:

given,

current in right direction

I₁ = 10 A

I₂ = 5 A

I₃ = 8 A

Length of Wire 2 = 15 cm

distance between wire 1 and wire 2, r₁ = 5 cm

distance between wire 2 and 3 = r₂ = 17 - 5 = 12 cm

Force on wire 2 due to current in wire 1 and wire 2

$F_2 = B_1I_2L_2 - B_3I_2L_2$

$F_2 =(B_1 - B_3)I_2L_2$

$F_2 =\dfrac{\mu_0}{4\pi}(\dfrac{2I_1}{r_1} -\dfrac{2I_3}{r_3} )I_2L_2$

μ₀ =absolute permeability of free space= 4π x 10⁻⁷ H/m

$F_2 =\dfrac{4\pi \times 10^{-7}}{4\pi}(\dfrac{2\times 10}{0.05} -\dfrac{2\times 8}{0.12})\times 5\times 0.15$

F_2 = 20 x 10⁻⁶ N

8 0

2 years ago

The area of a triangle is 30 m². Using the equation A=12bh A = 1 2 b h , where b is base and h is height, solve for h if b = 3 m

Mama L [17]

Answer:

20 metres

Explanation:

Given that the area of a triangle is 30 square metres (m²). Using the equation A = 1/2bh, this is the formula for the triangle.

where b is base and h is height

Given that b = 3 metres.

To calculate h, Substitute b and A into the equation

30 = 1/2 × 3 × h

3h = 60

h = 60/3

h = 20 m

Therefore, h is equal to 20 metres

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2 years ago

Which of the following quantities provide enough information to calculate the tension in a string of mass per unit length μ that

Bad White [126]

Answer:

A. the wave speed v and Wavelength

Explanation:

Given that

Mass density per unit length=μ

Frequency = f

The velocity V given as

$\mu=\dfrac{T}{V^2}\ kg/m$

$V=\sqrt{\dfrac{T}{\mu}}$

T=Tension

V=Velocity

V= f λ

λ=Wavelength

Therefore to find the tension ,only wavelength and speed is required.

The answer is A.

8 0

2 years ago

In an experiment, an object is released from rest from the top of a building. Its speed is measured as it reaches a point that i

NikAS [45]

Answer:

so the speed will increase by 1.44 times then the initial speed if the distance is increased to double

Explanation:

As we know that the air friction or resistance due to air is neglected then we can use the equation of kinematics here

$v_f^2 - v_i^2 = 2 a d$

since we released it from rest so we have

$v_i = 0$

so here we have

$v_f = \sqrt{2gd}$

now if the distance is double then we have

$v_f' = \sqrt{2g(2d)}$

now from above two equations we can say that

$v_f' = \sqrt2 v_f$

so the speed will increase by 1.44 times then the initial speed if the distance is increased to double

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3 years ago

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TiliK225 [7]

Explanation:

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2 years ago

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