What is the proper name for Zn(CIO)2?
2 answers:
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Answer:
1.33 × 10²⁴ molecules CO₂
General Formulas and Concepts:
<u>Chemistry - Stoichiometry</u>
- Reading a Periodic Table
- Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
97.3 g CO₂
<u>Step 2: Define conversions</u>
Avogadro's Number
Molar Mass of C - 12.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol
<u>Step 3: Convert</u>
= 1.33138 × 10²⁴ molecules CO₂
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules.</em>
1.33138 × 10²⁴ molecules CO₂ ≈ 1.33 × 10²⁴ molecules CO₂
The theoretical yield of silver chloride, AgCl is 5.2109 g
The balanced equation for the reaction is given below:
<h3>3AgNO₃(aq) + AICI₃(aq) —> Al(NO₃)₃ (aq) + 3AgCl (s) </h3>Next, we shall determine the mass of aluminum chloride, AICI₃ that reacted and the mass of silver chloride, AgCl produced from the balanced equation. This is illustrated below:
Molar mass of AICI₃ = 133.34 g/mol
Mass of AICI₃ from the balanced equation = 1 × 133.34 = 133.34 g
Molar mass of AgCl = 143.32 g/mol
Mass of AgCl from the balanced equation = 3 × 143.32 = <em>429.96 g</em>
<h3>SUMMARY</h3>From the balanced equation above,
133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.
Finally, we shall determine the theoretical yield of AgCl by the reaction of 1.616 g of AICI₃ as follow:
From the balanced equation above,
133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.
Therefore,
1.616 g of AICI₃ will react to produce = = 5.2109 g of AgCl.
Thus, the theoretical yield of silver chloride, AgCl is 5.2109 g
Learn more: brainly.com/question/24653699
Answer:
650 mmol.
Explanation:
The equation for the fermentation of one mole of glucose is:
C₆H₁₂O₆ + 2 NAD⁺ + 2 ADP + 2 P i + 2 NADH → 2 EtOH + 2 ATP + 2 NADH + 2 NAD⁺
Since NAD⁺/NADH is used and regenerated, we can eliminate it from the equation:
C₆H₁₂O₆ + 2 ADP + 2 P i → 2 EtOH + 2 ATP
With the equation, we calculate the maximum amount of ethanol that could be obtained theoretically:
1000 mmol C₆H₁₂O₆ ------------ 2000 mmol EtOH
325 mmol C₆H₁₂O₆ ------------- x= 650 mmol EtOH
Therefore, the maximum amount of ethanol that could be produced is 650 mmol.
