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3 years ago

Would you want the starting reactants in an airbag system to have higher density or a lower density

Chemistry

1 answer:

scZoUnD [109]3 years ago

8 0

Answer:

Explanation:

The de velopment of airbags began with the idea for a system that would ... of deaths or serious injuries decrease when an airbag and seat belt are used, ... An airbag must be able to deploy in a matter of milliseconds from the initial ... as hard as stone-- not the protective cushion you would want to crash into! ... Reactants ...

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A sodium atom has 11 protons and 12 neutrons. What is the mass number of this sodium atom?

Jlenok [28]

Sodium has a mass number of 23amu. Since sodium has 11 protons, the number of neutrons must be 23 – 11 = 12 neutrons.

3 0

3 years ago

Which of these equations are correct? Select all that apply

nikitadnepr [17]

Answer:

The answer to your question is below

Explanation:

There are 4 laws of gases

- Charles

$\frac{V1}{T1} = \frac{V2}{T2}$

- Gay Lussac

$\frac{P1}{T1} = \frac{P2}{T2}$

- Boyle - Mariotte

P1V1 = P2V2

- General law of gases

$\frac{P1V1}{T1} = \frac{P2V2}{T2}$

Let's use these formulas to answer the question

p2 = V2/P1 This is not a law of gases

p1= V1/k This formula is similar to Boyle mariotte equation

but is not.

V2 = k/P2 This equation is correct is Boyle Mariotte formula

V2 = P1V1/ P2 This equation is also correct is Boyle Mariotte formula

V1 = P1/P2 (V2) This equation is incorrect

P2 = (P1) V1/V2 This equation is correct is Boyle mariotte formula

4 0

4 years ago

Plz help me I swear to God i will mark you brainiest

Marat540 [252]

I think it’s b hope that helped

3 0

3 years ago

Why does the less reactive ion participate in electrolysis, instead of the higher reactive metal??

GuDViN [60]

Answer:

In a reactivity series, the most reactive element is placed at the top and the least reactive element at the bottom. More reactive metals have a greater tendency to lose electrons and form positive ions .

Explanation:

Yes ur well come

3 0

4 years ago

What should be the mole fraction of O2 in the gas mixture the diver breathes in order to have the same partial pressure of oxyge

Nutka1998 [239]

The question is incomplete, here is the complete question:

A scuba diver is at a depth of 355 m, where the pressure is 36.5 atm.

What should be the mole fraction of $O_2$ in the gas mixture the diver breathes in order to have the same partial pressure of oxygen in his lungs as he would at sea level? Note that the mole fraction of oxygen at sea level is 0.209.