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3 years ago

Give an example of each type of intermolecular forces (dispersion,

Chemistry

1 answer:

Andrei [34K]3 years ago

8 0

I’m not too sure I hope someone answers for you

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Please answer ................

nataly862011 [7]

Answer:

Explanation:

i. SO2

ii. Na2O

3 0

2 years ago

3. Methyl acetate is hydrolyzed at 25 oC in acidic environment. Aliquots of equal volume are removed and titrated with NaOH solu

avanturin [10]

Solution :

Time (sec) Volume of NaOH (mL)

339 26.23

1242 27.80

2745 29.70

4546 3.81

$\infty$ 39.81

Now the example of the first order kinetics w.r.t volumetric analysis is :

$k=\frac{2.303}{t} \log \left(\frac{v_{\infty}-v_0}{v_{\infty}- v_t}\right)$

Here, $v_{\infty}= \text{ volume at }\infty = 39.81$

$v_{t}= \text{ volume at time 't' } = 27.80$

$v_0$ = volume at time 0 = 0

Since the interval is not constant, we take the time interval as

$=\frac{903+1503+1801}{3}$

$=\frac{4207}{3}$

= 1402.3333

≈ 1402 seconds

$k=\frac{2.303}{1402} \log \left(\frac{39.81-0}{39.81-27.80}\right)$

$=(0.001643) \log \left(\frac{39.81}{10.01}\right)$

= 0.001643 x 0.52045

= 0.00082

$= 8.55 \times 10^{-4} \ sec^{-1}$

Therefore, the first order rate constant is k $= 8.55 \times 10^{-4} \ sec^{-1}$ .

5 0

3 years ago

Calculate the work done when a force of 500N moves an object 20m. and (B) if it

strojnjashka [21]

Answer:

work done = force multiplied by distance covered,which is 500n multiplied by 20 m= 10000nm

power= work done/time

p= 10000/10

p=1000

4 0

3 years ago

What Kelvin temperature is the same as -13° Celsius?

zavuch27 [327]

Answer:

Degrees Kelvin = Degrees Celsius + 273.15

Degrees Kelvin = -13 + 273.15

= 260.15 °

Explanation:

8 0

3 years ago

If a solution has a pOH of 8.71, what is the [H+]?

TEA [102]

Answer: $5.1\times 10^{-6}M$

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

$pH+pOH=14$

Putting in the values:

$pH=14-8.71=5.29$

$5.29=-log[H^+]$

$[H^+]=5.1\times 10^{-6}$

Thus $[H^+]$ is $5.1\times 10^{-6}M$

6 0

4 years ago