3 years ago

If 68 is 40% of a value, what is the value?

Mathematics

2 answers:

Anika [276]3 years ago

8 0

60 divided by 0.4(40%)=150

=150

Dmitriy789 [7]3 years ago

6 0

68 = 40%

34 = 20%

34 * 5 = 170
20 * 5 = 100%

The value is 170.

You might be interested in

Pls I neeed help very hard

Fynjy0 [20]

Answer:

96 ft

Step-by-step explanation:

Well add the given numbers up and calculate unkown sides using given measurments

6 0

2 years ago

Which models show 60%? Check all that apply.

goldfiish [28.3K]

Answer:

OPTION A AND B.

AS OPTION A IS 3/5=6/10=60%

Option C=60/100=60%

6 0

3 years ago

Read 3 more answers

What is the slope-intercept form of them equation of a line that passes through (5, -4) and has a slope of 3/4?

EastWind [94]

C is correct answer, passes through (5,-1) and also has slope of 3/4

5 0

3 years ago

Evaluate g(x) = 1.873 -0.0034x +0.5 for x = 1 and x = 2.

AlexFokin [52]

Answer:

g(1) = 1.8696

g(2) = 1.8662

Step-by-step explanation:

Simply plug in the x values into the equation in a calc and you should get your answer.

6 0

3 years ago

Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur

Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

$\sigma$ is parameterized by

$\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle$

for $0\le u\le7$ and $0\le v\le\frac{2\pi}3$ , and a normal vector to this surface is

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle$

with norm

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}$

So the integral of $f(x,y,z)=x^2+y^2+z^2$ is

$\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}$

6 0

3 years ago