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vekshin1
2 years ago
10

The midpoint of AB is M(1, 6). If the coordinates of A are (8, 4), what are the coordinates of B?

Mathematics
1 answer:
Ne4ueva [31]2 years ago
4 0

Answer:

(-6,8)

Step-by-step explanation:

8+x2=2       4+y2=12

x2= -6         y2= 8

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Which number goes in the box?<br> 8 + 9 = 9 +
Ira Lisetskai [31]

Answer:

8

Step-by-step explanation:

I hope this helps you out!

7 0
2 years ago
Read 2 more answers
n 2018, homes in East Baton Rouge (EBR) Parish sold for an average of $239,000. You take a random sample of homes in Ascension p
Olenka [21]

Answer:

Conclusion

   There is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean

Step-by-step explanation:

From the question we are told that

   The population mean for EBR is  \mu_ 1  = \$239,000

    The sample mean for Ascension parish  is \= x_2  = \$246,000

   The  p-value  is  p-value  =  0.045

     The level of significance is  \alpha = 0.01

The null hypothesis is  H_o : \mu_2  = \mu_1

The  alternative hypothesis is  H_a  :  \mu_2 > \mu_1

Here \mu_2 is the population mean for Ascension parish

   From the data given values we see that  

          p-value  >  \alpha

So we fail to reject the null hypothesis

So we conclude that there is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean

3 0
3 years ago
Solve the proportion: 5/x+7=3/x+3
Allushta [10]

Answer:

x=3

Step-by-step explanation:

cross multiply

5(x+3)=3(x+7)

5x+15=3x+21

5x+15-3x=3x+21-3x

2x+15=21

2x+15-15=21-15

2x=6

x=3

7 0
2 years ago
The junior and senior classes at Central High School were asked to choose a destination for a field trip. The results are shown
Ann [662]

Solution:

We are given below frequency table:

             Amusement-Park      Museum         Broadway-Show         Total

Juniors                57                      21                      42                          120

Seniors                64                     44                      58                          166

Total                    121                     65                      100                        286

We have to find the percentage of surveyed students who chose the amusement park.

From the table, we see there are total 121 students who chose amusement park out of total 286 students.

Therefore, the percentage of surveyed students who chose the amusement park is given below:

\frac{121}{286}\times 100=42.3\%

Hence, the option A. 42.30% correct.


3 0
2 years ago
Highest/greatest common factor of 50 and 125
Nata [24]
50 =2×5×5 125=5×5×5 Hoghest common factor = 5×5 =25
5 0
2 years ago
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