What is the multiplicative inverse of 10 upon -2

Mathematics

1 answer:

Mandarinka [93]2 years ago

3 0

Answer:

The multiplicative Inverse of any number except zero, is 1 over the number

Step-by-step explanation:

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Simplify the expression by combining like terms if possible. If not possible select already simplified. 4a^2+2a+4a^2-5

vichka [17]

So the expression is: $4 a^{2} + 2a + 4 a^{2} - 5$

You can combine like terms, which are terms that contain the same variables raised to the same power. That means you can combine the two $4 a^{2}$ . $4 a^{2} + 4 a^{2} = 8 a^{2}$ The other terms can't be combined.

Your final answer should be $8 a^{2} +2a-5$ .

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Secants L J and L M intersect and form an angle at point L. Solve for x.

german

Answer:

x = 14

Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

$\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}$

Check:

$\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}$