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3 years ago

How many 1/5 make 14/10

Mathematics

2 answers:

Tems11 [23]3 years ago

7 0

Answer:

There are 7 1/5 in 14/10

Step-by-step explanation:

say the unknown is x

1/5 x = 14/10

x = 14/10 × 5

x = 7

Zinaida [17]3 years ago

5 0

Answer:

<h2>There are seven 1/5's in 14/10.</h2>

Step-by-step explanation:

To know how many 1/5 make 14/10, we just need to find a factor that makes them equal. The following expression can help to that aim

$\frac{1}{5}x=\frac{14}{10}$

Then, we solve for $x$

$x=\frac{14 \times 5}{10}\\ x=\frac{70}{10}\\ x=7$

Therefore, there are seven 1/5's in 14/10.

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Simplify to an equivalent exponential expression. Use 5 as the base. 53.54 ### 22 53.54 = 0 (Type your answer using exponential

Dominik [7]

Answer:

5⁷

Step-by-step explanation:

simple explanation- add the exponets 4+3=7

add the exponet of 7 to 5 so 5⁷

5 0

3 years ago

Ill give brainliest pls help i am so stuck

jok3333 [9.3K]

Answer:

Part A:

Since the slopes of the lines are not equal, the pair of equations for lines A and B will have one solution.

Part B:

(3 ,5 ) is the solution to the equations of lines A and B.

Step-by-step explanation:

Part A:

We are required to determine the number of solutions that the pair of equations for lines A and B have. To do this, we shall determine the slope of each line;

A straight line labeled A joins the ordered pair 2, 6 with the ordered pair 6, 2. The slope is defined as;

(change in y) / (change in x)

The slope of line A is thus;

(2 - 6)/(6 - 2) = -1

A straight line B joins the ordered pair 0, 3 with the ordered pair 4.5, 6.

On the other hand, the slope of line B is;

(6 - 3) / (4.5 - 0) = 2/3

Since the slopes of the lines are not equal, the pair of equations for lines A and B will have one solution.

Part B:

What is the solution to the equations of lines A and B?

We first need to determine the equation of each line;

Line A, the slope was found to be -1 and the line passes through (2,6)

The equation of the line in slope intercept form is;

y = -x + c

6 = -2 + c

c = 8

y = -x + 8

On the other hand, the slope of line B was found to be 2/3 and the line passes through (0,3). Therefore, we have;

y = 2/3x + c

3 = 2/3 (0) + c

c= 3

y = (2/3)x + 3

The graph of these two lines is shown in the attachment below. The lines intersect at (3 ,5 ) which is the solution to the equations of lines A and B.

The graphical solution to a system of linear equations is given by the point of intersection of the two lines representing each equation.