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xxMikexx [17]
3 years ago
6

I NEED HELP PLEASE, THANKS! :)

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
4 0
(I’m currently on mobile so sorry for possible bad formatting)

First, recall the trig identity: tan(A-B)=(tan(A)-tan(B))/(1+tan(A)tan(B))

We see that the given equation directly corresponds with this, with A=9x and B=5x.

Thus we can equate the given equation to tan(9x-5x)=tan(4x)
This cannot be simplified further.
KIM [24]3 years ago
3 0

Answer:  tan(14x)

<u>Step-by-step explanation:</u>

Consider the Sum Formula for tan:

tan(A + B)=\dfrac{tan(A)+tan(B)}{1-tan(A)(tan(B)}\\\\\\tan(9x+5x)=\dfrac{tan(9x)+tan(5x)}{1-tan(9x)(tan(5x)}\\\\\\\large\boxed{tan(14x)}=\dfrac{tan(9x)+tan(5x)}{1-tan(9x)(tan(5x)}

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Anyone know the answerr ill mark u as brainlist.5star. and like ​
konstantin123 [22]

Answer:

31.53

Step-by-step explanation:

6% of 525.50 is 31.53

8 0
3 years ago
F ∠BAC = 17° and ∠CED = 17° are the two triangles, ΔBAC and ΔCED similar? If so, by what criterion?
diamong [38]
<span>yes, by AA criterion</span>
5 0
3 years ago
Read 2 more answers
Can someone help please
Phoenix [80]

9514 1404 393

Answer:

  16x +8h

Step-by-step explanation:

Use the given function arguments and simplify.

  \dfrac{f(x+h)-f(x)}{h}=\dfrac{8(x+h)^2-8x^2}{h}=\dfrac{8(x^2+2hx+h^2)-8x^2}{h}\\\\=\dfrac{8x^2 +16xh+8h^2-8x^2}{h}=\dfrac{16xh+8h^2}{h}=\boxed{16x +8h}

7 0
3 years ago
HEY CAN ANYONE HELP ME!
nataly862011 [7]

Answer:

Given: In triangle ABC and triangle DBE where DE is parallel to AC.

In ΔABC and ΔDBE

DE || AC   [Given]

As we know, a line that cuts across two or more parallel lines.  In the given figure, the line AB is a transversal.

Line segment  AB is transversal that intersects two parallel lines.  [Conclusion from statement 1.]

Corresponding angles theorem: two parallel lines are cut by a transversal, then the  corresponding angles are congruent.

then;

\angle BDE \cong \angle BAC  and

\angle BEC \cong \angle BCA

Reflexive property of equality states that if angles in geometric figures can be congruent to themselves.

by Reflexive property of equality:

\angle B \cong \angle B  

By AAA (Angle Angle Angle) similarity postulates states that all three pairs of corresponding angles are the same then, the triangles are similar

therefore, by AAA similarity postulates theorem

\triangle ABC \sim \triangle DBE

Similar triangles are triangles with equal corresponding angles and proportionate side.

then, we have;

\frac{BD}{BA}                  [By definition of similar triangles]

therefore, the missing statement and the reasons are

Statement                                                                   Reason

3.\angle BDE \cong \angle BAC      Corresponding angles theorem

and  \angle BEC \cong \angle BCA        

5. \triangle ABC \sim \triangle DBE   AAA similarity postulates    

6. BD over BA                                                    Definition of similar triangle



7 0
3 years ago
Read 2 more answers
REWARDING BRAINLY FOR CORRECT ANSWER
AlexFokin [52]
It is statistical because there can be a variety of answers.
6 0
3 years ago
Read 2 more answers
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