Answer:
Radius: 19 yards
Diameter: 38 yards
Circumference: 119. 32
Step-by-step explanation:
Radius
To find the radius you divide the diameter by 2 because, the diameter is a; a straight line passing from side to side through the center of a body or figure, especially a circle or sphere.
So 38 ÷ 2 = 19
So the radius is 19.
_____________________
Circumference
To find the Circumference you need to do 2·π·19
C=2·π
2·π = 6.28
6.28 · 19 = 119. 32
Circumference is 119. 32
Answer:
a) -7 & b) -6
Step-by-step explanation:
Here,
a) x = 0
Solution ↦
b) x = -1
Solution ↦
Answer:
B. 30
Step-by-step explanation:
Given.:
m<4 = 2x°
m<5 = 4x°
Required:
Value of x
Solution:
<4 and <5 are angles in a straight line, therefore:
m<4 + m<5 = 180°
Substitute
2x + 4x = 180°
6x = 180°
x = 180/60
x = 30
In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.
<h3>
What is an electron?</h3>
- The electron is a subatomic particle with a negative one elementary charge electric charge.
- Electrons are the first generation of the lepton particle family and are widely regarded as elementary particles due to the lack of known components or substructure.
Electron in the hydrogen:
- Hydrogen has the simplest electron configuration to write because it just contains one electron.
- There is essentially only one electron surrounding the Hydrogen nucleus.
- Because hydrogen only has one electron, its configuration is 1s1.
- The maximum occurs at a0, the first Bohr radius, in a plot showing the chance of finding the electron in the hydrogen ground state vs the distance from the nucleus.
Therefore, in a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.
Know more about electrons here:
brainly.com/question/860094
#SPJ4
The complete question is given below:
In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs:
A. at a0. the first Bohr radius
B. at slightly less than a0
C. at slightly more than a0
D. at 2 a0
E. at a0/2
the answer is 192 i did this test and got 192
