Question

A cylindrical rod has a length of 27 cm and a diameter of 1.6 mm. What is the cross-sectional area in 10-6 m2?

Answer 1

Answer: The cross-sectional area of the cylindrical rod is $2.01\times 10^{-6}m^2$

Explanation:

We are given a cylindrical rod whose cross-sectional area will be in the form of circle.

To calculate the area of circle, we use the equation:

$\text{Area}=\pi r^2$

where,

r = radius of the rod = $\frac{d}{2}=\frac{1.6mm}{2}=0.8mm=0.8\times 10^{-3}m$    (Conversion factor: 1 m = 1000 mm)

Putting values in above equation, we get:

$\text{Area}=3.14\times (0.8\times 10^{-3})^2\\\\\text{Area}=2.01\times 10^{-6}m^2$

Hence, the cross-sectional area of the cylindrical rod is $2.01\times 10^{-6}m^2$