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dimaraw [331]
3 years ago
15

How many molecules are there in 42 grams of AIF3

Chemistry
1 answer:
Sever21 [200]3 years ago
7 0

Answer:

The correct answer is - 3.012×10^23  molecules

Explanation:

The number of molecules is present in any mole of an element or compound are the same. To find the molecules you need to multiply the number of the moles of the compound by Avogadro's number:

Moles are calculated from the molecular weight, for AlF3

= 26.98 + 3×19

= 26.98 + 57

= 83.98

Then moles in 42 grams:

= 42/83.98

= 0.5001190 moles

Now the number of molecules = moles*Avogadro's number

= 0.500110×6.022×10^23

= 3.011×10^23  molecules

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m_a_m_a [10]

Answer:

To allow all the elements or compounds to separate complete.

Explanation:

In chromatography, the compounds need some space and time to separate, one from each other, if you  just use the half of the paper strip maybe you will not notice the different spots of compounds. Remember all the substances have different affinity for the solvents, that means, some react very quickly but others need more time as the colors that conform the black color in an ink.

4 0
3 years ago
How much iodine (I2), in grams, should be added to water to produce 2.5L of solution with a molarity of 0.56M?
denis-greek [22]

Molarity=Moles of solute/Volume of solution in L

So

  • 0.56M=moles/2.5L
  • moles=0.56(2.5)
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Mads of Iodine

  • Moles(Molar mass)
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7 0
2 years ago
I’ll give brainlyiest (sorry if I spelled it wrong) to first correct answer
user100 [1]

Answer:

Dependent variable

Hope this helps :)

Have a great day !

5INGH

Brainliest please

Explanation:

8 0
3 years ago
What is the wavelength of these waves?
Pepsi [2]
It measure the distance between two consecutive waves within the phase.
3 0
3 years ago
How many moles of sodium are needed to produce 2.4 mol of sodium oxide?
Lorico [155]

Answer:

Explanation:

4

N

a

+

O

2

→

2

N

a

2

O

.

By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol

N

a

2

O

should result.

Explanation:

The molecular mass of natrium oxide is

61.98

g

⋅

m

o

l

−

1

. If

5

m

o

l

natrium react, then

5

2

m

o

l

×

61.98

g

⋅

m

o

l

−

1

=

154.95

g

natrium oxide should result.

So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go.

3 0
3 years ago
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