<h3>
Answer:</h3>
3 moles SO₂ and 3 moles SO₃
<h3>
Explanation:</h3>
We are given;
Mass of sulfur dioxide is 192 grams
Molar mass of sulfur dioxide is 64 g/mol
We are required to determine number of moles of sulfur dioxide and those of sulfur trioxide produced.
<h3>Step 1: Writing the equation for the reaction </h3>
The equation for the reaction is, 2SO₂(g) + O₂(g) → 2SO₃(g)
<h3>Step 2: Calculating the number of moles of sulfur dioxide </h3>
Moles of a compound = Mass of a compound ÷ Molar mass of the compound
Moles of SO₂ = 192 grams ÷ 64 g/mol
= 3 moles
Therefore, moles of sulfur dioxide that reacted are 3 moles
<h3>Step 3: Determining moles of SO₃ produced </h3>
From the equation, two moles of SO₂ reacts to produce two moles of SO₃
Therefore, the mole ratio of SO₂ to SO₃ is 1:1
Thus; number of moles of SO₃ will be equal to the number of moles of SO₂
Hence, Moles of SO₃ = 3 moles
