Question

If 192 grams of sulfur dioxide are reacted completely, determine both the number of moles and of sulfur dioxide reacted (the formula mass for sulfur dioxide is 64g/mol) and the number of miles of sulfur trioxide produced

Answer 1

Answer:

3 moles SO₂ and 3 moles SO₃

Explanation:

We are given;

Mass of sulfur dioxide is 192 grams

Molar mass of sulfur dioxide is 64 g/mol

We are required to determine number of moles of sulfur dioxide and those of sulfur trioxide produced.

Step 1: Writing the equation for the reaction

The equation for the reaction is, 2SO₂(g) + O₂(g) → 2SO₃(g)

Step 2: Calculating the number of moles of sulfur dioxide

Moles of a compound = Mass of a compound  ÷ Molar mass of the compound

Moles of SO₂ = 192 grams ÷ 64 g/mol

                      = 3 moles

Therefore, moles of sulfur dioxide that reacted are 3 moles

Step 3: Determining moles of SO₃ produced

From the equation, two moles of SO₂ reacts to produce two moles of SO₃

Therefore, the mole ratio of SO₂ to SO₃ is 1:1

Thus; number of moles of SO₃ will be equal to the number of moles of SO₂

Hence, Moles of SO₃ = 3 moles