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Airida [17]
3 years ago
8

Which of the following can take the shape of the container it is in but has a fixed volume? (3 points)

Chemistry
2 answers:
tresset_1 [31]3 years ago
8 0

the answer is liquid bromine.

IrinaK [193]3 years ago
4 0
Easy, that's liquid sir.
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Aluminum can react with oxygen gas to produce aluminum oxide, what time of reaction is this?
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This is known as a synthesis reaction. A+B->C
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3 years ago
64. Which of the followings can dissociate in water?
Arisa [49]

Answer:

<h2>Hi there !</h2>

<h2>C. HCl</h2>

Explanation:

<h2>Reason :-</h2>

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8 0
2 years ago
Read 2 more answers
You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from
GuDViN [60]

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

The balanced chemical reaction will be,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.08 mole of HCl neutralizes by 0.08 mole of NaOH

Thus, the number of neutralized moles = 0.08 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = 200mL+200L=400mL

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 400mL=400g

Now we have to calculate the heat absorbed during the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

c = specific heat of water = 4.18J/g^oC

m = mass of water = 400 g

T_{final} = final temperature of water = 27.78^oC=273+25.10=300.78K

T_{initial} = initial temperature of metal = 25.10^oC=273+27.78=298.1K

Now put all the given values in the above formula, we get:

q=400g\times 4.18J/g^oC\times (300.78-298.1)K

q=4480.96J

Thus, the heat released during the neutralization = -4480.96 J

Now we have to calculate the enthalpy of neutralization.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of neutralization = ?

q = heat released = -4480.96 J

n = number of moles used in neutralization = 0.08 mole

\Delta H=\frac{-4480.96J}{0.08mole}=-56012J/mole=-56.012kJ/mol

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 56.012 kJ/mole

8 0
3 years ago
How do many types of cells, like bacteria, reproduce?
umka2103 [35]

Answer:

cells like bacteria are bisexual so they split and their offspring is 100 percent like the parent and this process happens over and over

Explanation:

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2 years ago
The ------------- the temperature of an object, the faster the molecules vibrate.
labwork [276]
Higher, they have more energy so they move faster
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3 years ago
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