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Alja [10]
3 years ago
15

Using 25.0cm3 of aqueous lithium hydroxide, concentration 2.48mol/dm3, 2.20g of hydrated lithium sulfate was obtained. Calculate

the percentage yield, giving your answer to one decimal place.
2LiOH H2SO4 → Li2SO4 2H2O Li2SO4 H2O → Li2SO4.H2O
The number of moles of LiOH used = .......................
The number of moles of Li2SO4.H2O which could be formed = .......................
Mass of one mole of Li2SO4.H2O = 128 g
The maximum yield of Li2SO4.H2O = .......................
percentage yield = .......................% [4]​
Chemistry
1 answer:
klemol [59]3 years ago
3 0

Answer:

I do not no so ask some one else

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Answer:

<h2>13.82 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

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From the question we have

n =  \frac{8.32 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 13.820598...

We have the final answer as

<h3>13.82 moles</h3>

Hope this helps you

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